java - AssertJ - 检查类后继续流畅的断言

Question

假设我有一个Map<String, Action>我是这样的:

    assertThat( spyActionMap.get( "a" ) ).isInstanceOf( Action.class );

...通过。现在我想检查Action得到的是正确的:

    assertThat( spyActionMap.get( "a" ) ).isInstanceOf( Action.class ).getValue( Action.NAME ).isEqualTo( "Go crazy" );

...无法编译，这并不奇怪。有什么办法可以做到这种事情吗？

Answer 1

您可以尝试isInstanceOfSatisfying并在 Consumer 中指定您的断言:

Object yoda = new Jedi("Yoda", "Green");
Object luke = new Jedi("Luke Skywalker", "Green");

Consumer<Jedi> jediRequirements = jedi -> {
   assertThat(jedi.getLightSaberColor()).isEqualTo("Green");
   assertThat(jedi.getName()).doesNotContain("Dark");
};

assertThat(yoda).isInstanceOfSatisfying(Jedi.class, jediRequirements);
assertThat(luke).isInstanceOfSatisfying(Jedi.class, jediRequirements);