我使用 Java AWT 创建了以下随机拼图。在程序开始时，如您所见，所有数字均按顺序排列。我想生成不重复的随机数。这个怎么做？我应该使用 Random类(class)？
import java.awt.*;
import java.awt.event.*;
class Puzzle extends Frame implements ActionListener
{
Button b1,b2,b3,b4,b5,b6,b7,b8,b9;
Puzzle()
{
setTitle("Shuffle");
setSize(500,500);
setLayout(new GridLayout(3,3));
setVisible(true);
Font f=new Font("Arial",Font.BOLD,100);
b1=new Button("1");
b1.setFont(f);
b1.addActionListener(this);
b2=new Button("2");
b2.setFont(f);
b2.addActionListener(this);
b3=new Button("3");
b3.setFont(f);
b3.addActionListener(this);
b4=new Button("4");
b4.setFont(f);
b4.addActionListener(this);
b5=new Button("5");
b5.setFont(f);
b5.addActionListener(this);
b6=new Button("6");
b6.setFont(f);
b6.addActionListener(this);
b7=new Button("7");
b7.setFont(f);
b7.addActionListener(this);
b8=new Button("8");
b8.setFont(f);
b8.addActionListener(this);
b9=new Button(" ");
b9.setFont(f);
b9.addActionListener(this);
add(b1); add(b2); add(b3);
add(b4); add(b5); add(b6);
add(b7); add(b8); add(b9);
}
public void actionPerformed(ActionEvent ae)
{
if(ae.getSource() == b1)
{
if(b2.getLabel() == " ")
{
b2.setLabel(b1.getLabel());
b1.setLabel(" ");
}
else if(b4.getLabel() == " ")
{
b4.setLabel(b1.getLabel());
b1.setLabel(" ");
}
}
if(ae.getSource() == b2)
{
if(b1.getLabel() == " ")
{
b1.setLabel(b2.getLabel());
b2.setLabel(" ");
}
else if(b3.getLabel() == " ")
{
b3.setLabel(b2.getLabel());
b2.setLabel(" ");
}
else if(b5.getLabel() == " ")
{
b5.setLabel(b2.getLabel());
b2.setLabel(" ");
}
}
if(ae.getSource() == b3)
{
if(b2.getLabel() == " ")
{
b2.setLabel(b3.getLabel());
b3.setLabel(" ");
}
else if(b6.getLabel() == " ")
{
b6.setLabel(b3.getLabel());
b3.setLabel(" ");
}
}
if(ae.getSource() == b4)
{
if(b1.getLabel() == " ")
{
b1.setLabel(b4.getLabel());
b4.setLabel(" ");
}
else if(b5.getLabel() == " ")
{
b5.setLabel(b4.getLabel());
b4.setLabel(" ");
}
else if(b7.getLabel() == " ")
{
b7.setLabel(b4.getLabel());
b4.setLabel(" ");
}
}
if(ae.getSource() == b5)
{
if(b2.getLabel() == " ")
{
b2.setLabel(b5.getLabel());
b5.setLabel(" ");
}
else if(b4.getLabel() == " ")
{
b4.setLabel(b5.getLabel());
b5.setLabel(" ");
}
else if(b6.getLabel() == " ")
{
b6.setLabel(b5.getLabel());
b5.setLabel(" ");
}
else if(b8.getLabel() == " ")
{
b8.setLabel(b5.getLabel());
b5.setLabel(" ");
}
}
if(ae.getSource() == b6)
{
if(b3.getLabel() == " ")
{
b3.setLabel(b6.getLabel());
b6.setLabel(" ");
}
else if(b5.getLabel() == " ")
{
b5.setLabel(b6.getLabel());
b6.setLabel(" ");
}
else if(b9.getLabel() == " ")
{
b9.setLabel(b6.getLabel());
b6.setLabel(" ");
}
}
if(ae.getSource() == b7)
{
if(b4.getLabel() == " ")
{
b4.setLabel(b7.getLabel());
b7.setLabel(" ");
}
else if(b8.getLabel() == " ")
{
b8.setLabel(b7.getLabel());
b7.setLabel(" ");
}
}
if(ae.getSource() == b8)
{
if(b5.getLabel() == " ")
{
b5.setLabel(b8.getLabel());
b8.setLabel(" ");
}
else if(b7.getLabel() == " ")
{
b7.setLabel(b8.getLabel());
b8.setLabel(" ");
}
else if(b9.getLabel() == " ")
{
b9.setLabel(b8.getLabel());
b8.setLabel(" ");
}
}
if(ae.getSource() == b9)
{
if(b6.getLabel() == " ")
{
b6.setLabel(b9.getLabel());
b9.setLabel(" ");
}
else if(b8.getLabel() == " ")
{
b8.setLabel(b9.getLabel());
b9.setLabel(" ");
}
}
}
public static void main(String args[])
{
new Puzzle();
}
}
最佳答案
你可以这样做:
// global scope
List<Integer> container = new ArrayList<>();
//populate it
for(int i =1; i<=8; i++){
container.add(i);
}
..........
..........
..........
public static int getRandom(){
//to refill it if ya need to call it more than 8 times
//if(container.size()==0){for(int i=1; i<=8; i++){container.add(i);}
Random generator = new Random();
Integer randomNumber = container.get(generator.nextInt(container.size()));
container.remove(randomNumber);
return randomNumber;
}
此外，如果您想用 1 到 8 之间的唯一数字随机命名/标记每个按钮，只需执行以下操作:
b1=new Button(String.valueOf(getRandom()));
等等。
关于java - 如何生成1到8的随机数而不重复？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/45042598/