java - Spring Hibernate 验证 - 每个字段获取一条错误消息

标签 java spring-mvc bean-validation hibernate-validator

我正在努力为每个字段只获取一条错误消息。我对每个领域都有很多规则,我想一一验证它们。如果失败,验证将停止并仅返回一条描述该字段失败规则的消息。

经过研究,我发现了类似 @ReportAsSingleViolation 注释的东西,它有点工作,但它修复了来自自定义约束的消息。所以这不是我想要的。

我已经阅读过有关 @GroupSequence 的内容,但我无法让它像我所描述的那样工作。

这是我的具有自定义约束规则的实体:

@Entity
@Table(name = "users", schema = "myschema")
public class User {
    private int id;

    @ValidLogin
    private String login;

    @ValidPassword
    private String password;

    @ValidEmail
    private String email;

    //getters & setters
}

并使用几个内置规则实现我的自定义约束:

@Constraint(validatedBy = UsernameValidator.class)
@Target(ElementType.FIELD)
@Retention(RetentionPolicy.RUNTIME)
@NotEmpty
@Pattern(regexp = "^[a-zA-Z0-9]*$")
@Length.List({
        @Length(min = 3 , message = "{Length.min.user.login}"),
        @Length(max = 30, message = "{Length.max.user.login}")
})
public @interface ValidLogin {

    String message() default "";

    Class<?>[] groups() default {};

    Class<? extends Payload>[] payload() default { };
}

默认情况下,我会在 jsp View 中收到失败规则的每条消息。所以,我想让它像这样工作:检查规则 @NotEmpty,如果失败,则返回适当的消息,如果不验证下一个规则 @Pattern 等等。

你能帮忙吗?非常感谢!

最佳答案

我想,这就是您正在寻找的内容:

@Test
public void test() {
    Validator v = Validation.byProvider( HibernateValidator.class )
            .configure()
            .buildValidatorFactory()
            .getValidator();

    // validations for each group - shows only corresponding violations even if other constraints
    // are violated as well
    assertThat( v.validate( new Bar( null, null ), First.class ) ).hasSize( 2 );
    assertThat( v.validate( new Bar( "", "" ), Second.class ) ).hasSize( 2 );
    assertThat( v.validate( new Bar( "a", "a" ), Third.class ) ).hasSize( 2 );

    // shows that validation will go group by group as defined in the sequence:
    //NotNull
    Set<ConstraintViolation<Bar>> violations = v.validate( new Bar( null, null ) );
    assertThat( violations ).hasSize( 2 );
    assertThat( violations ).extracting( "message" ).containsOnly( "must not be null" );

    //NotBlank
    violations = v.validate( new Bar( "", "" ) );
    assertThat( violations ).hasSize( 2 );
    assertThat( violations ).extracting( "message" ).containsOnly( "must not be blank" );

    //Size
    violations = v.validate( new Bar( "a", "a" ) );
    assertThat( violations ).hasSize( 2 );
    assertThat( violations ).extracting( "message" ).containsOnly( "size must be between 5 and 2147483647" );

}

@GroupSequence({ First.class, Second.class, Third.class, Bar.class })
private static class Bar {

    @NotNull(groups = First.class)
    @NotBlank(groups = Second.class)
    @Size(min = 5, groups = Third.class)
    private final String login;

    @NotNull(groups = First.class)
    @NotBlank(groups = Second.class)
    @Size(min = 5, groups = Third.class)
    private final String password;

    public Bar(String login, String password) {
        this.login = login;
        this.password = password;
    }
}

interface First {
}

interface Second {
}

interface Third {
}

我添加了一个测试,以便可以看到验证是如何逐组进行的。为了实现这样的行为,您需要为您的 bean 重新定义默认组序列。为此,您需要在要验证的 bean 上放置 @GroupSequence 注释,然后列出您需要的所有组,并且不要忘记添加 bean 类本身(如下所示)例子)。所有这些信息也都存在 here - 在文档中。


编辑

如果您同意不使用标准约束,那么您可能会执行以下操作:

    @Test
public void test2() throws Exception {
    Set<ConstraintViolation<Foo>> violations = validator.validate( new Foo( "", null ) );
    assertThat( violations ).hasSize( 2 );
    assertThat( violations ).extracting( "message" )
            .containsOnly( "value should be between 3 and 30 chars long", "Value cannot be null" );
}

private static class Foo {

    @ValidLogin
    private final String login;

    @ValidLogin
    private final String password;

    public Foo(String login, String password) {
        this.login = login;
        this.password = password;
    }
}

@Target({ FIELD })
@Retention(RUNTIME)
@Documented
@Constraint(validatedBy = { ValidLogin.ValidLoginValidator.class })
@interface ValidLogin {
    String message() default "message";

    Class<?>[] groups() default { };

    Class<? extends Payload>[] payload() default { };

    class ValidLoginValidator implements ConstraintValidator<ValidLogin, String> {
        private static final Pattern PATTERN = Pattern.compile( "^[a-zA-Z0-9]*$" );

        @Override
        public boolean isValid(String value, ConstraintValidatorContext context) {
            String message = "";
            if ( value == null ) {
                message = "Value cannot be null";
            }
            else if ( !PATTERN.matcher( value ).matches() ) {
                message = "Value should match pattern ";
            }
            else if ( message.length() < 3 || message.length() > 30 ) {
                message = "value should be between 3 and 30 chars long";
            }
            if ( !message.isEmpty() ) {
                context.disableDefaultConstraintViolation();
                context.buildConstraintViolationWithTemplate( message ).addConstraintViolation();
            }
            return false;
        }
    }
}

在这种情况下,您只需拥有自己的自定义约束和 validator 。然后你逐个检查,然后根据第一次失败的检查构建违规行为。如果您对登录名和密码执行类似的检查,那么您还可以提取诸如 patternminmax 之类的内容作为约束的属性,但对于字符串长度具有不同模式的示例...

关于java - Spring Hibernate 验证 - 每个字段获取一条错误消息,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45859113/

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