java - 正则表达式 : mark every match in the string and return the string edited with marks, Java

Question

目标是用括号标记字符串中的每个匹配项，并为每个匹配项标记返回相同的字符串

即:

Pattern = "\\d+"
Text = "e3e3e"
wanted result = "e(3)e(3)e"

我尝试过:

while (matcher.find())
text = text.replace(match.group(), "(" + match.group() + ")");

但每次找到匹配项时它都会一遍又一遍地替换所有匹配项

e3e3e => e((3))e((3))e instead of e(3)e(3)e
h4h444h = > h(4)h(4)(4)(4)h  instead of h(4)h(444)h

Answer 1

您可以将匹配项替换为 ($0)，其中 $0 代表整个匹配项:

String Pattern = "\\d+";
String Text = "e3e3e";
System.out.println(Text.replaceAll(Pattern, "($0)"));

请参阅Java demo和 regex demo .

Java Pattern docs这么说

Group zero always stands for the entire expression.