java - @RequestMapping 不起作用 - 没有找到处理程序方法

标签 java rest spring-mvc spring-boot servlets

我在使@RequestMapping工作时遇到问题,我收到以下日志;你能帮我理解日志吗?

启动时记录:

DEBUG o.s.web.servlet.DispatcherServlet - DispatcherServlet with name 'dispatcherServlet' processing GET request for [/ruler/webjars/test]

DEBUG o.s.w.s.m.m.a.RequestMappingHandlerMapping - Looking up handler method for path /webjars/test

DEBUG o.s.w.s.m.m.a.RequestMappingHandlerMapping - Did not find handler method for [/webjars/test]

DEBUG o.s.w.s.h.SimpleUrlHandlerMapping - Matching patterns for request [/webjars/test] are [/webjars/, /]

DEBUG o.s.w.s.h.SimpleUrlHandlerMapping - URI Template variables for request [/webjars/test] are {}

DEBUG o.s.w.s.h.SimpleUrlHandlerMapping - Mapping [/webjars/test] to HandlerExecutionChain with handler [ResourceHttpRequestHandler [locations=[class path resource [META-INF/resources/webjars/]], resolvers=[org.springframework.web.servlet.resource.PathResourceResolver@52454457]]] and 1 interceptor

DEBUG o.s.web.servlet.DispatcherServlet - Last-Modified value for [/ruler/webjars/test] is: -1

DEBUG o.s.web.servlet.DispatcherServlet - Null ModelAndView returned to DispatcherServlet with name 'dispatcherServlet': assuming HandlerAdapter completed request handling

DEBUG o.s.web.servlet.DispatcherServlet - Successfully completed request

访问localhost:80/ruler/test时记录:

DEBUG o.s.web.servlet.DispatcherServlet - DispatcherServlet with name 'dispatcherServlet' processing GET request for [/ruler/test]

DEBUG o.s.w.s.m.m.a.RequestMappingHandlerMapping - Looking up handler method for path /test

DEBUG o.s.w.s.m.m.a.RequestMappingHandlerMapping - Did not find handler method for [/test]

DEBUG o.s.w.s.h.SimpleUrlHandlerMapping - Matching patterns for request [/test] are [/**]

DEBUG o.s.w.s.h.SimpleUrlHandlerMapping - URI Template variables for request [/test] are {}

DEBUG o.s.w.s.h.SimpleUrlHandlerMapping - Mapping [/test] to HandlerExecutionChain with handler [ResourceHttpRequestHandler [locations=[class path resource [META-INF/resources/], class path resource [resources/], class path resource [static/], class path resource [public/], ServletContext resource [/]], resolvers=[org.springframework.web.servlet.resource.PathResourceResolver@4538856f]]] and 1 interceptor

DEBUG o.s.web.servlet.DispatcherServlet - Last-Modified value for [/ruler/test] is: -1

DEBUG o.s.web.servlet.DispatcherServlet - Null ModelAndView returned to DispatcherServlet with name 'dispatcherServlet': assuming HandlerAdapter completed request handling

DEBUG o.s.web.servlet.DispatcherServlet - Successfully completed request

应用程序属性:

server.servlet.context-path=/ruler
server.port=80

休息 Controller :

    @RestController
public class myController {
    private final MedicalService medicalService;

    @Autowired
    public myController(MedicalService medicalService) {
        this.medicalService = medicalService;
    }

    @RequestMapping(value="/test")
    public String testRest()
    {
        return "Yay";
    }
}

没有 web.xml。

最佳答案

找到了我的问题的答案 here ,这是因为项目结构,而不是配置。

应用程序包应该像com.app,然后 Controller 将是com.app.controller

关于java - @RequestMapping 不起作用 - 没有找到处理程序方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51966987/

相关文章:

java - 用于提取信息的正则表达式

java - 在 Controller 中调用特定操作

java - 对于 JVM 应用程序,是否有充分的理由使用 Elasticsearch REST API?

java - 无法找到命名空间 ('context' 的 NamespaceHandler)

java - 如何使用 ITextRenderer 在每个页面上添加页眉和页脚

java - 升级到 JRE7 会抛出 java.lang.NoClassDefFoundError

java - 我如何在 java 代码中优化这个 mySQL 事务?

java - For 循环内的 For 循环 - ListArrays - Android、Java!

jQuery .ajax() POST 请求在 RESTful WCF 上抛出 405(方法不允许)

node.js - 如何将标准 API 错误响应制定为 Loopback 4 中的对象?