我一直在开发:
public List<DepartmentType> getAllDepartmentTypes() {
return session.getCurrentSession()
.createCriteria(DepartmentType.class)
.addOrder(Order.asc("department_type_name"))
.list();
}
地点:
@Autowired
SessionFactory session;
来自this Question关于 createCriteria()
的替代方案,我创建了一个获取列表的方法:
public List<DepartmentType> getAllDepartmentTypes() {
CriteriaBuilder builder = session.getCurrentSession().getCriteriaBuilder();
CriteriaQuery<DepartmentType> criteriaQuery = builder.createQuery(DepartmentType.class);
return session.getCurrentSession()
.createQuery(criteriaQuery)
.getResultList();
}
但我还是不知道在哪里使用:
addOrder(Order.asc("department_type_name"))
最佳答案
您需要使用CriteriaQuery.orderBy()
提供 order by 子句。
public List<DepartmentType> getAllDepartmentTypes() {
CriteriaBuilder builder = session.getCurrentSession().getCriteriaBuilder();
CriteriaQuery<DepartmentType> criteriaQuery = builder.createQuery(DepartmentType.class);
Root<DepartmentType> deptType = criteriaQuery.from(DepartmentType.class);
criteriaQuery.select(deptType).orderBy(builder.asc(deptType.get("department_type_name")));
return session.getCurrentSession()
.createQuery(criteriaQuery)
.getResultList();
}
关于java - session.getCurrentSession().createCriteria(MyClass.class) 已弃用如何使用 .addOrder() 现在,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54615252/