java - 彩票程序忽略功能

Question

我打算编写一个程序，依次列出一个随机数，它确实做到了(伴随着一声蜂鸣声)。然而，它忽略了程序正确运行所需的基本功能。 Ask() 函数执行其含义，它要求用户输入范围 (1000-9999) 之间的整数，然后将其与获胜数字(随机)进行比较，以查看用户是否正确猜对并因此获胜。我最近才开始用 Java 写作，所以我不太确定我是否犯了一个基本错误。任何帮助将不胜感激!

package edu.pupr.pega4;
import java.awt.Toolkit;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.Date;
import java.util.Scanner;
import javax.swing.JOptionPane;
import javax.swing.Timer;
public class Pega4Driver {
    public static void main(String[] args) {
        Pega4 test = new Pega4(2000, true);
        test.start();
        JOptionPane.showMessageDialog(null, "Quit program?");
        JOptionPane.showMessageDialog(null, "Perdiste!!!");
        System.exit(0);
    }
}

class Pega4 {
    private int interval; //Time interval for new number to appear
    private boolean beep; //BEEP
    private int number; //The input number
    private int tiradas = 1; //Counter
    private int winNum; //The winning number 
    //Constructor
    public Pega4(int interval, boolean beep) {
        this.interval = interval;
        this.beep = beep;
    }
    //Returns a random number within a specified range
    public double getRandomIntegerBetweenRange(double min, double max){
        double x = (int)(Math.random()*((max-min)+1))+min;
        return x;
    }
    public void start() {
        class Pega4Inner implements Asker, ActionListener {
            Scanner input = new Scanner(System.in);
            Date now = new Date();
            @Override
            public void ask() {
                System.out.println("Entrar numero deseado: ");
                number = input.nextInt();
                //Input Validation
                if (number < 1000 || number > 9999)
                {
                    System.out.println("Entrada invalida. Entrar numero deseado: ");
                    number = input.nextInt();
                }
                System.out.println(now);
            }
            @Override
            public void actionPerformed(ActionEvent e) {
                winNum = (int) getRandomIntegerBetweenRange(1000, 9999);
                System.out.println("Tirada #" + (tiradas++) + ": " + winNum);
                if (beep)
                    Toolkit.getDefaultToolkit().beep();
                if (winNum == number)
                {
                    JOptionPane.showMessageDialog(null, "Ganaste!!!");
                    System.exit(0);
                }
            }
        }
        ActionListener listener = new Pega4Inner();
        Timer timer = new Timer(interval, listener);
        timer.start();
    }
}

Pega4Inner 类实现了我创建的名为 Asker 的接口(interface)。其代码如下:

package edu.pupr.pega4;

public interface Asker {
    void ask();
}

Answer 1

您需要从某个地方实际调用您的 ask() 方法:) 我认为在当前代码中执行此操作的正确点是在 Pega4Inner 中的 actionPerformed() 方法的开头:

 public void actionPerformed(ActionEvent e) {
     ask();
     winNum = (int) getRandomIntegerBetweenRange(1000, 9999);
     …

编辑

根据您仅调用 ask() 一次的要求，一种方法是从内部类中取出此方法并将其放入外部类中，然后在你的司机级别。因此，您的 Pega4 类可能如下所示:

class Pega4 {
    private int interval; //Time interval for new number to appear
    private boolean beep; //BEEP
    private int number; //The input number
    private int tiradas = 1; //Counter
    private int winNum; //The winning number 
    //Constructor
    Date now = new Date();
    Scanner input = new Scanner(System.in);

    public Pega4(int interval, boolean beep) {
        this.interval = interval;
        this.beep = beep;
    }

    //Returns a random number within a specified range
    public double getRandomIntegerBetweenRange(double min, double max) {
        double x = (int) (Math.random() * ((max - min) + 1)) + min;
        return x;
    }

    public void ask() {
        System.out.println("Entrar numero deseado: ");
        number = input.nextInt();
        //Input Validation
        while (number < 1000 || number > 9999) { // not IF here
            System.out.println("Entrada invalida. Entrar numero deseado: ");
            number = input.nextInt();
        }
        System.out.println(now);
    }

    public void start() {
        class Pega4Inner implements ActionListener {

            @Override
            public void actionPerformed(ActionEvent e) {
                // ask();
                winNum = (int) getRandomIntegerBetweenRange(1000, 9999);
                System.out.println("Tirada #" + (tiradas++) + ": " + winNum);
                if (beep) {
                    Toolkit.getDefaultToolkit().beep();
                }
                if (winNum == number) {
                    JOptionPane.showMessageDialog(null, "Ganaste!!!");
                    System.exit(0);
                }
            }
        }
        ActionListener listener = new Pega4Inner();
        Timer timer = new Timer(interval, listener);
        timer.start();
    }
}

然后在您的 Pega4Driver 类中:

...
Pega4 test = new Pega4(2000, true);
test.ask();
test.start();
...