我用这段代码来绘制我的图的边缘, 如果用户想在 Flow 模式下查看图形,那么我绘制箭头而不是线条,一切都完美,直到我更改窗口大小,然后箭头起点 (x1,y1) 与我的节点不同步移动,使它们保持未连接,而drawLine() 工作完美。
这与 AffineTransform 有关吗?
(箭头绘制方法来自here))
void drawArrow(Graphics g1, int x1, int y1, int x2, int y2) {
Graphics2D g = (Graphics2D) g1.create();
int arrowSize = 5;
double dx = x2 - x1, dy = y2 - y1;
double angle = Math.atan2(dy, dx);
int len = (int) Math.sqrt(dx*dx + dy*dy);
AffineTransform at = AffineTransform.getTranslateInstance(x1, y1);
at.concatenate(AffineTransform.getRotateInstance(angle));
g.setTransform(at);
g.drawLine(0, 0, len, 0);
g.setStroke(new BasicStroke(1));
g.drawLine(len/3, arrowSize , len/3-3*arrowSize, 0);
g.drawLine(len/3, -arrowSize , len/3-3*arrowSize, 0);
}
对于那些想了解 Paint Edge 方法是什么样子的人:
public void paintEdge(Graphics g) {
Point uCenter = u.getCenter();
Point vCenter = v.getCenter();
g.setColor(color);
Graphics2D g2=(Graphics2D) g;
g2.setStroke(new BasicStroke(3));
if (mode==Mode.FLOW) {
int minx=Math.min(uCenter.x, vCenter.x),miny=Math.min(uCenter.y, vCenter.y);
int maxx=Math.max(uCenter.x, vCenter.x),maxy=Math.max(uCenter.y, vCenter.y);
g2.drawString(""+ f + " / " + c,10+minx + (maxx-minx)/2,10+miny+ (maxy- miny)/2);
drawArrow(g2,uCenter.x, uCenter.y, vCenter.x, vCenter.y);
} else {
g2.drawLine(uCenter.x, uCenter.y, vCenter.x, vCenter.y);
}
g2.setStroke(new BasicStroke(1));
}
最佳答案
void drawArrow(Graphics2D g, int x1, int y1, int x2, int y2) {
AffineTransform prev = g.getTransform();
int arrowSize = 5;
double dx = x2 - x1, dy = y2 - y1;
double angle = Math.atan2(dy, dx);
int len = (int) Math.sqrt(dx*dx + dy*dy);
AffineTransform at = AffineTransform.getTranslateInstance(x1, y1);
at.rotate(angle);
g.transform(at);
g.drawLine(0, 0, len, 0);
g.setStroke(new BasicStroke(1));
g.drawLine(len/3, arrowSize , len/3-3*arrowSize, 0);
g.drawLine(len/3, -arrowSize , len/3-3*arrowSize, 0);
g.setTransform(prev);
}
对于任何想知道的人来说,这就是它的完成方式。
问题是,我使用了 g.setTransform(at);而不是 g.transform(at); 这很难。
关于java - 仿射变换,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9121188/