Java 将每一行读入单独的数组

Question

我的文本文件中有 1,000 行数据，我希望每一行都有自己的 float []。

1,1,1,1,1,1
2,2,2,2,2,2
3,3,3,3,3,3

会导致:

 float[0] = {1,1,1,1,1,1}
 float[1] = {2,2,2,2,2,2}
 float[2] = {3,3,3,3,3,3}

这可能吗？我只能找到将整个文件加载到数组中的示例。我尝试对所有数组进行硬编码，但超出了 ~65,000 的字节字符限制

Answer 1

尝试以下操作:

// this list will store all the created arrays
List<float[]> arrays = new ArrayList<float[]>();

// use a BufferedReader to get the handy readLine() function
BufferedReader reader = new BufferedReader(new FileReader("myfile.txt"));

// this reads in all the lines. If you only want the first thousand, just
// replace these loop conditions with a regular counter variable
for (String line = reader.readLine(); line != null; line = reader.readLine()) {
    String[] floatStrings = line.split(",");
    float[] floats = new float[floatStrings.length];
    for (int i = 0; i < floats.length; ++i) {
        floats[i] = Float.parseFloat(floatStrings[i]);
    }
    arrays.add(floats);
}

请注意，我没有添加任何异常处理(例如 readLine()，抛出 IOException)。