java - 谷歌地点 API 的 GSON 解析

Question

我需要一些帮助来创建将填充 GSON 解析器的类。 这是自动完成 Google Places API 的输出:

{
   "predictions" : [
  {
     "reference" : "CjQtAA",
     "terms" : [
        {
           "offset" : 0,
           "value" : "Ladimirevci"
        },
        {
           "offset" : 13,
           "value" : "Hrvatska"
        }
     ],
     "types" : [ "locality", "political", "geocode" ]
  },
  {
     "reference" : "CjQtAAA",
     "terms" : [
        {
           "offset" : 0,
           "value" : "Ladimirevci"
        },
        {
           "offset" : 13,
           "value" : "Hrvatska"
        }
     ],
     "types" : [ "locality", "political", "geocode" ]
  }
],
  "status" : "OK"
}

解决方案感谢 MikO

类(class)有:

public class GPlacesAPIResults {

    @SerializedName("predictions")
    public List<GPlacesAPILocation> predictions;

    @SerializedName("status")
    public String status;

}

第二:

public class GPlacesAPILocation implements Serializable {

    private static final long serialVersionUID = 4509808527882750586L;

    @SerializedName("reference")
    private String reference;

    @SerializedName("terms")
    private List<GPlacesAPIAddress> terms;

    @SerializedName("types")
    private List<String> types;

    }

第三:

public class GPlacesAPIAddress implements Serializable {

    private static final long serialVersionUID = -6916297127791361853L;

    @SerializedName("value")
    public String value;

    }

在应用程序中我这样调用它

InputStreamReader in = new InputStreamReader(conn.getInputStream()); //results from places api

GPlacesAPIResults lcs = new Gson().fromJson( in , GPlacesAPIResults.class);

感谢您的努力:-)

Answer 1

你的带有属性locations的Result类没有任何意义......事实上我不明白你为什么想出这个，因为没有JSON 中任意位置的 locations 元素!

尝试这样的事情(遵循您的特定符号):

Results
List<Locations> predictions;
String status;

Locations
String reference;
List <Addresses> terms;

Addresses
String value;