我正在用 java 编写拼写检查器功能。我面临着一个麻烦,
当我在 Text
中输入一些文本时。从中我如何获取当前输入或当前修改的单词,以便我可以
验证当前输入或修改的单词是否在我的词典中找到。
我已经通过用红色下划线突出显示了字典中找不到的单词。但我是通过阅读整个文本的每次修改来实现这一点的。
最佳答案
我设法将一些代码放在一起,但不会迭代整个文本。相反,它从当前光标位置左右移动,搜索单词的结尾。当找到两端时,输出单词:
public static void main(String[] args)
{
Display display = Display.getDefault();
final Shell shell = new Shell(display);
shell.setText("StackOverflow");
shell.setLayout(new GridLayout(2, false));
Text text = new Text(shell, SWT.BORDER);
GridData data = new GridData(SWT.FILL, SWT.BEGINNING, true, true);
data.horizontalSpan = 2;
text.setLayoutData(data);
new Label(shell, SWT.NONE).setText("Current word:");
final Label label = new Label(shell, SWT.NONE);
text.addListener(SWT.Verify, new Listener()
{
@Override
public void handleEvent(Event e)
{
Text source = (Text) e.widget;
/* Construct the entered text */
String oldString = source.getText();
String textString = oldString.substring(0, e.start) + e.text + oldString.substring(e.end);
/* Get all the chars */
char[] text = textString.toCharArray();
/* Get the cursor position */
int position = source.getCaretPosition();
/* Adjust cursor position based on input (necessary for delete operations) */
if(e.text.equals(""))
position--;
else
position++;
/* Remember start and end of current word */
int leftBorder = -1;
int rightBorder = -1;
/* Search for left end of the current word */
for(int i = 1; i < position; i++)
{
int left = position - i;
if(left > 0)
{
if(!Character.isLetter(text[left]))
{
leftBorder = left + 1;
break;
}
}
}
/* Search for right end of the current word */
for(int i = position; i < text.length; i++)
{
int right = i;
if(right < text.length)
{
if(!Character.isLetter(text[right]))
{
rightBorder = right;
break;
}
}
}
/* If the word is the first/last, set border accordingly */
if(leftBorder == -1)
leftBorder = 0;
if(rightBorder == -1)
rightBorder = text.length;
StringBuilder result = new StringBuilder();
/* Output the word */
for(int i = leftBorder; i < rightBorder; i++)
result.append(text[i]);
label.setText(result.toString());
shell.layout(true, true);
}
});
shell.pack();
shell.setSize(600, 100);
shell.open();
while (!shell.isDisposed())
{
if (!display.readAndDispatch())
display.sleep();
}
display.dispose();
}
以下是突出显示当前编辑的单词的两个屏幕截图:
<小时/>
因此,如果整个文本的长度为 n
并且当前单词的长度为 m
,则运行时间将为 O(m)
O(n)
。
关于java - 如何从 SWT TextBox 获取当前输入/修改的单词,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19013209/