我有一个可以很好地处理其他请求映射的 Controller ,但我在使用 @PathVariable
注释时遇到了困难。
在 this example (请参阅“URI 模板模式”)它有以下示例:
@RequestMapping(value="/owners/{ownerId}", method=RequestMethod.GET)
public String findOwner(@PathVariable String ownerId, Model model) {
Owner owner = ownerService.findOwner(ownerId);
model.addAttribute("owner", owner);
return "displayOwner";
}
我的代码如下所示:
@RequestMapping( value="/ViewReport/json", method = RequestMethod.GET)
public ModelAndView TestJson(final Model model){
model.addAttribute("fnord", "{\"hello\":\"awesome\"}");
return new ModelAndView("reportViewJson");
}
@RequestMapping( value="/ViewReport/jayson/{foobar}", method = RequestMethod.GET)
public ModelAndView TestJayz(final Model model, @PathVariable String foobar){
model.addAttribute("fnord", "{\"hello\":\""+foobar+"\"}");
return new ModelAndView("reportViewJson");
}
然后我有一个包含以下内容的 web.xml
文件:
<servlet-mapping>
<servlet-name>autoreport</servlet-name>
<url-pattern>/ViewReport/jayson/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>autoreport</servlet-name>
<url-pattern>/ViewReport/json</url-pattern>
</servlet-mapping>
现在,当我导航到 /ViewReport/json
时,我得到了 JSON {"hello": "awesome"}
正如我所期望的。但是,当我导航到 /ViewReport/jayson/42
时,我得到
HTTP Status 404 -
type Status report
message
description The requested resource () is not available.
Apache Tomcat/7.0.29
我使用 PathVariable
时做错了什么,我需要做什么来修复它?
更新
当我的服务器启动时,它会输出这些行:
[ INFO] 14:15(AbstractUrlHandlerMapping.java:registerHandler:315)
Mapped URL path [/ViewReport/json.*] onto handler 'reportViewController'
[DEBUG] 14:15(AbstractBeanFactory.java:doGetBean:246)
Returning cached instance of singleton bean 'reportViewController'
[ INFO] 14:15(AbstractUrlHandlerMapping.java:registerHandler:315)
Mapped URL path [/ViewReport/json/] onto handler 'reportViewController'
[DEBUG] 14:15(AbstractBeanFactory.java:doGetBean:246)
Returning cached instance of singleton bean 'reportViewController'
[ INFO] 14:15(AbstractUrlHandlerMapping.java:registerHandler:315)
Mapped URL path [/ViewReport/jayson/{foobar}] onto handler 'reportViewController'
当我提出请求时,我得到:
[DEBUG] 20:45(DispatcherServlet.java:doService:823)
DispatcherServlet with name 'autoreport' processing GET request for [/ViewReport/jayson/fnord]
[ WARN] 20:45(DispatcherServlet.java:noHandlerFound:1108)
No mapping found for HTTP request with URI [/ViewReport/jayson/fnord] in DispatcherServlet with name 'autoreport'
最佳答案
Spring 有魔力;参数顺序很重要。 尝试颠倒处理程序参数的顺序。 而不是这个:
public ModelAndView TestJayz(final Model model, @PathVariable String foobar)
试试这个:
public ModelAndView TestJayz(@PathVariable String foobar, final Model model)
采取2:
尝试将 web.xml 中的映射更改为更通用的内容。例如:
<servlet-mapping>
<servlet-name>autoreport</servlet-name>
<url-pattern>/ViewReport/*</url-pattern>
</servlet-mapping>
我在测试 web.xml 中使用了 /spring/*
,在 Controller 中使用了 @RequestMapping("/blammy/{value}") ,然后将请求发送到“{WEBROOT}/spring/blammy/testvalue”,其中“{WEBROOT}”是我的测试应用程序的网络根目录。
关于java - 在Java+Spring中如何正确使用@PathVariable?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20575776/