Java掷骰子游戏While循环随机数生成

Question

好吧，我正在尝试创建一个骰子游戏，其中 args[0] 是玩游戏的次数。游戏.... 掷两个骰子，如果总和不等于 7，则将其值添加到总和中。如果总和等于 7，则游戏结束。我想跟踪所有游戏中最大的总和和最小的总和，该总和应该始终为零，因为当总和等于 7 时，它会将总和设置为 0。 这是我的代码。我不认为它打印的内容是我想要的...帮助？另外我如何在 Eclipse 中自动格式化？

public class diceGame {
    public static void main(String[] args) {
        int dice1;
        int dice2;
        int count=0;
        int theSum=0;
        int lowest=500;
        int finalSum=0;
        int diceSum=0;
        while (count !=Integer.parseInt(args[0])){
            count=count+1;
            theSum=0;
            while(diceSum!=7){
                diceSum=0;
                dice1=1 + (int)(Math.random() * ((6 - 1) + 1));
                dice2=1 + (int )(Math.random() * ((6 - 1) + 1));
                diceSum=dice1+dice2;
                if (diceSum !=7){
                    theSum=theSum+diceSum;
                if (theSum>finalSum){
                    finalSum=theSum;
                    }
                if (theSum<lowest){
                    lowest=theSum;
                }


                }

                }
            }
        System.out.println("After "+args[0]+" simulations: ");
        System.out.println("Biggest sum: "+finalSum);
        System.out.println("Smallest sum: "+lowest);
    }
    }

我修好了

public class diceGame {
    public static void main(String[] args) {
        int dice1;
        int dice2;
        int count = 0;
        int theSum = 0;
        int lowest = Integer.MAX_VALUE;
        int finalSum = 0;
        int diceSum;
        int totalSum=0;
        while (count < Integer.parseInt(args[0])) {
            count = count + 1;
            diceSum=0;
            theSum=0;
            while (diceSum!=7) {
                diceSum = 0;
                dice1 = 1 + (int) ((Math.random() * (6 - 1)) + 1);
                dice2 = 1 + (int) ((Math.random() * (6 - 1)) + 1);
                diceSum = dice1 + dice2;
                if (diceSum != 7) {
                    theSum = theSum + diceSum;
                }
                //System.out.println("the sum is "+theSum);
            }
            if (theSum > finalSum) {
                finalSum = theSum;
            }
            if (theSum < lowest) {
                lowest = theSum;
            }
            totalSum=totalSum+theSum;
        }
        double average=(double)totalSum/(Double.parseDouble(args[0]));
        System.out.println("After " + args[0] + " simulations: ");
        System.out.println("Biggest sum: " + finalSum);
        System.out.println("Smallest sum: " + lowest);
        System.out.println("The average is: "+average);

    }
}

Answer 1

这是因为 2 个骰子相加时的最低值是 2，而不是 0。如果你在第一次掷骰子时掷出 7，那么你将不会更新你的最大和最低值。您需要将这些检查移到循环之外。

        while(diceSum!=7){
            diceSum=0;
            dice1=1 + (int)(Math.random() * ((6 - 1) + 1));
            dice2=1 + (int )(Math.random() * ((6 - 1) + 1));
            diceSum=dice1+dice2;
            if (diceSum !=7) {
                theSum=theSum+diceSum;
            }
        }
        if (theSum>finalSum){
            finalSum=theSum;
        }
        if (theSum<lowest){
            lowest=theSum;
        }