以下程序编码和解码包含 Map<Integer, List<Integer>> 的类字段。
解码后，映射中的列表包含字符串，而不是整数。
有没有一种简单的方法来确保列表将填充整数而不是 解码期间的字符串？
import java.io.StringReader;
import java.io.StringWriter;
import java.util.Arrays;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import javax.xml.bind.annotation.XmlRootElement;
import org.eclipse.persistence.jaxb.JAXBContextFactory;
import org.eclipse.persistence.jaxb.MarshallerProperties;
import org.eclipse.persistence.oxm.MediaType;
public class MapApp {
@XmlRootElement
public static class Publication {
private String name;
private Map<Integer, List<Integer>> yearToIssues;
public void setName(String name) {
this.name = name;
}
public String getName() {
return name;
}
public void setYearToIssues(Map<Integer, List<Integer>> yearToIssues) {
this.yearToIssues = yearToIssues;
}
public Map<Integer, List<Integer>> getYearToIssues() {
return yearToIssues;
}
}
public static void main(String[] args) throws JAXBException {
Publication publication = new Publication();
publication.setName("JAXB miracles");
Map<Integer, List<Integer>> yearToIssues = new HashMap<>();
yearToIssues.put(2013, Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12));
yearToIssues.put(2014, Arrays.asList(1, 2));
publication.setYearToIssues(yearToIssues);
String marshalled = marshal(publication);
Publication uPublication = unmarshal(Publication.class, marshalled);
List<Integer> issues = uPublication.getYearToIssues().get(2013);
if (((Object) issues.get(0)) instanceof String) {
System.out.println("issue is instance of String!");
}
}
static String marshal(Object toMarshal) throws JAXBException {
JAXBContext jc = JAXBContextFactory.createContext(new Class[] {toMarshal.getClass()}, null);
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.setProperty(MarshallerProperties.MEDIA_TYPE, MediaType.APPLICATION_XML);
StringWriter sw = new StringWriter();
marshaller.marshal(toMarshal, sw);
System.out.println(sw);
return sw.toString();
}
static <T> T unmarshal(Class<T> entityClass, String str) throws JAXBException {
JAXBContext jc = JAXBContextFactory.createContext(new Class[] {entityClass}, null);
Unmarshaller unmarshaller = jc.createUnmarshaller();
unmarshaller.setProperty(MarshallerProperties.MEDIA_TYPE, MediaType.APPLICATION_XML);
return (T) unmarshaller.unmarshal(new StringReader(str));
}
}
最佳答案
您需要写一个XmlAdapter对于 Map<Integer, List<Integer>>正确处理这个用例。
关于java - 如何编码/取消编码 Map<Integer, List<Integer>>？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/21684854/