java - 如何清除文件中的注释？ (也许是正则表达式)

Question

我有一个包含此文本的文件

@Entity
@Table(name = "User")
public class User implements LSLEntity, HasUUID {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "id")
    private Long id;

    @Column(name = "facebook_id", unique=true)
    private String facebookId;

    @UUID
    @Column(name = "uuid", unique = true)
    private String uuid;

    @OneToOne(cascade = CascadeType.ALL)
    @JoinColumn(name="user_info_id")
    private UserInfo userInfo;

    @OneToOne
    @JoinColumn(name="balanced_customer_id")
    @Transient
    private BalancedCustomer balancedCustomer;

    @OneToOne(mappedBy = "user")
    private Session session;

我需要清理文件中的注释。我编写了一个简单的 Java 程序，用于从文件下载数据

public class Test {
    public static void main(String[] args) throws IOException {
        File file = new File( "C:\\test.txt" );
        BufferedReader br = new BufferedReader (new InputStreamReader(new FileInputStream( file ), "UTF-8"));
        String line = null;
        while ((line = br.readLine()) != null) {
            System.out.println( line );
        }
        br.close();
    }
}

现在，我需要清理注释中的数据以最终发生

public class User implements LSLEntity, HasUUID {

private Long id;
private String facebookId;
private String uuid;
private UserInfo userInfo;
private BalancedCustomer balancedCustomer;
private Session session;

我想使用正则表达式。请告诉我一篇好的文章，或者例子，或者它可能有另一种解决问题的方法？

Answer 1

为什么要麻烦java呢？只需从命令行运行 grep -v ^@ [yourfile.java] 即可。

[编辑]

grep:

-v means invert-match: Selected lines are those not matching any of the specified patterns.

^ 表示匹配行首。这将匹配以 @

开头的行

顺便说一句，你也可以尝试 sed: sed '/^@/d' 测试