ios - 如何在 Swift3 中将 Any 转换为字典

Question

我使用 Alamofire 网络请求，想处理错误消息，

我的代码:

class NetWorkingEngine: NSObject {
    typealias CreateNetWorkBlockSuccess = (_ responseobject:Any) -> ();
    typealias CreateNetWorkBlockFail = (_ responseobject:NSDictionary) -> ();

    func getDataFun(URL:String,netWorkingBlockSuccess:@escaping CreateNetWorkBlockSuccess,netWorkingBlockField:@escaping CreateNetWorkBlockField) -> Void {
        Alamofire.request(URL).responseJSON { (responseObject) in
            if responseObject.result.isSuccess {
                netWorkingBlockSuccess(responseObject.data!);
            }else{
                netWorkingBlockFail(responseObject.result);
            }
        }
    }
}

但要排队

netWorkingBlockFail(responseObject.result)

错误

cannot convert value of type “Result<Any>” to expected argument type "NSDictionary"

我该怎么办？

更新: I want to resquert Error Info, if you error request,Error info is 'Any',But how to 'Error info' convert Dictionary?

Answer 1

您可以使用 [:] 类型将 Any 类型转换为 Dictionary。假设你有一个名为 person 的变量，它是 Any 类型；然后使用以下代码:

let personDictionary = (person as! [String:String])["name"]

...其中 name 是字典中的键。