Java程序: finding smallest and largest number of 3 numbers in an array

Question

下面的代码适用于最大值，但适用于它显示的最小值:对于我输入的任何 3 个值，最小数字为 0。非常感谢任何帮助。

import java.util.Scanner;

class MyClass{


        public static void main(String[] args) {
            // declare and create array object
            // declare smallest and largest int variables 
            int[] numbers;
            numbers = new int[3];
            int smallest = numbers[0], largest = numbers[0];

            // create Scanner object
            Scanner input = new Scanner(System.in);

            // prompt user 
            System.out.print("Please enter 3 numbers: \n");
            // use for loop to obtain user input
            for (int counter = 0; counter < numbers.length; counter++) {
                numbers[counter] = input.nextInt();
            } // end obtaining input

            // for loop to find largest and smallest values
            for (int i=0 ;i< numbers.length; i++) {
                if (numbers[i] < smallest) {
                    smallest = numbers[i];
                } // end finding smallest
                if (numbers[i] > largest) {
                    largest = numbers[i];
                } // end finding largest number       

            }

            System.out.println("largest number is "+largest);
            System.out.println("smallest number is "+smallest);

        }   

}

Answer 1

此处，Smallest 始终初始化为 0:intsmallest=numbers[0]。除非用户输入小于 0 的值，否则最小值将保持为 0。请使用 Integer.MAX_VALUE (intsmallest = Integer.MAX_VALUE) 来确保最小的数字将实际被选中。