java - java猜谜游戏的选择和计数验证帮助

Question

我在这里看到了很多这个问题，但内容要么太简单，要么比我想要做的更复杂。

我的具体问题是了解如何让程序在新游戏开始时重新开始尝试次数，因为它将继续计算上次停止的位置，以及验证是或否选择字符串。我们需要用不同的方法进行验证。我已经尝试了很多技术，但我无法验证任何内容，并且学习障碍也无济于事......

import java.util.Scanner;
import java.util.Random;
import java.lang.Math; 

public class Gamerandom {  
    public static void main( String[] args ) {
        System.out.println("Welcome to the Guess the Number Game ");
        System.out.println();
        System.out.println("I am thinking of a number between 1 and 100.");
        System.out.println("Try to guess it.");
        System.out.println();

        Scanner sc = new Scanner(System.in);

        int secretValue;
        secretValue = (int) (Math.random() * 99 + 1);
        int guess; 
        int tries = 0;
        String choice;
        boolean playing = true;

        while(playing) {  

        System.out.print("Enter number: ");
        guess = sc.nextInt();
        tries++;

        if (guess == secretValue) {
            if (tries <= 3) {
                System.out.println("You got it in " + tries + " tries.");
                System.out.println("Great Work! You are a mathematical wizard!");
            } else if (tries > 3 && tries <= 7) {
                System.out.println("You got it in " + tries + " tries.");
                System.out.println("Not too bad! You've got some potential. ");
            } else  {
                System.out.println("You got it in " + tries + " tries.");
                System.out.println("What took you so long? Maybe you should take some lessons.");
            }
         } else if (guess < secretValue) {
            System.out.println("Too low! Guess again. \n");
            continue;
        } else if (guess == secretValue +10) {
            System.out.println("Way too high! Guess again. \n");
            continue;
        } else if (guess > secretValue) {
            System.out.print("Too high! Guess again. ");
            continue;
        } 

        System.out.println("Try again? y/n");
        choice = sc.next();      
        }                   
    }  

    public static boolean getChoice(Scanner sc) {
        String choice = "y";
        boolean getChoice = true;

        while (!choice.equalsIgnoreCase("y") && !choice.equalsIgnoreCase("n")) {
            System.out.println("Error! Entry must be 'y' or 'n'. Try again");
            System.out.println("Try again? (y/n)");
            choice = sc.nextLine();
        }

        if (choice.equalsIgnoreCase("n")) {
            System.out.println("Bye - Come back again soon!");
            return true;
        } else {
            System.out.println("I am thinking of a number between 1 and 100.");
            System.out.println("Try to guess it. ");

        }
        return false;
        }  
    }

Answer 1

1. 更改此:

   else if (猜测== secret 值+10){ System.out.println("太高了!再猜一下。\n"); 继续；

   }

对此:

 else if (guess >= secretValue +10){
        System.out.println("Way too high! Guess again. \n");
        continue;

    }

您已经差不多知道是/否了...只需要进行一些调整。

更改此:

System.out.println("再试一次？y/n"); 选择= sc.next();
}

对此:

System.out.println("Try again? y/n");
        choice = sc.next();

        // This will set the boolean to continue the loop
        // or finish the program
        if (playing = getChoice(choice)){
            tries = 0;
        }

最后，您需要更改 getChoice() 方法。

更改此:

public static boolean getChoice(扫描仪 sc) { 字符串选择=“y”； boolean getChoice = true;

while (!choice.equalsIgnoreCase("y") && !choice.equalsIgnoreCase("n")) {
    System.out.println("Error! Entry must be 'y' or 'n'. Try again");
    System.out.println("Try again? (y/n)");
    choice = sc.nextLine();
}

if (choice.equalsIgnoreCase("n")) {
    System.out.println("Bye - Come back again soon!");
    return true;
} else {
    System.out.println("I am thinking of a number between 1 and 100.");
    System.out.println("Try to guess it. ");

}
return false;
}  

对此:

// Pass choice in as the parameter instead of a Scanner object
public static boolean getChoice(String choice) {

    // Create a new scanner object
    Scanner sc = new Scanner(System.in);

    while (!choice.equalsIgnoreCase("y") && !choice.equalsIgnoreCase("n")) {
        System.out.println("Error! Entry must be 'y' or 'n'. Try again");
        System.out.println("Try again? (y/n)");
        choice = sc.nextLine();
    }
    if (choice.equalsIgnoreCase("n")) {
        System.out.println("Bye - Come back again soon!");
        // This will close your loop and the program will end
        return false;
    } else {
        System.out.println("I am thinking of a number between 1 and 100.");
        System.out.println("Try to guess it. ");
        // This will cause your loop to continue
        return true;
    }
}

现在您只需要添加一些异常处理就可以开始工作了。祝你好运!