java - 从两个数量为 N 或更多的重叠字符串创建一个字符串？

Question

假设我有两个字符串，

str1 = "abcdefg"
str2 = "cdefghijkl"

如果用户指定了整数，则假设 n = 4。

如何确定两个字符串是否重叠 4 个或更多字符？ 在本例中，它们将“cdefg”重叠 5 个以形成“abcdefghijkl”

如果 n = 6 那么它们不会重叠，因为 "bcdefg"!= "cdefgh"

我遇到的问题是重叠是否比用户指定的多。

Answer 1

The issue I am having is if there is more overlap than user specified.

这就是循环的用武之地:从用户重叠定义的位置开始，并不断增加它，直到 (1) 检测到重叠或 (2) 用完其中一个字符串中的字符。

伪代码如下所示:

int userOverlap = ... // Get user overlap
int minLength = Math.min(stringOne.length(), stringTwo.length());
for (int overlap = userOverlap  ; overlap <= minLength; overlap++) {
    if (testOverlap(stringOne, stringTwo, overlap)) {
        return true;
    }
}
return false;

private static bool testOverlap(String a, String b, int overlap) {
    ... // This is your method that tests for one specific overlap
}