There are 2 arrays, one of int and one of Strings (words) ; sort both of them and then print it in a way that at odd places it should be words and at even numbers.
这是我的代码:
import java.util.*;
public class JavaApplication4 {
public static void main(String[] args) {
Scanner in=new Scanner(System.in);
int num[]=new int[10];
String str[]=new String[10];
String str1[]=new String[20];
for(int i=0; i<5; i++)//for taking strings
{
str[i]=in.next();
}
for(int i=0; i<5; i++)//for taking nums
{
num[i]=in.nextInt();
}
for(int i=0; i<5; i++)
{
System.out.println("The String are "+str[i]);
}
for(int i=0; i<5; i++)
{
System.out.println("The num are "+num[i]);
}
for (int i = 0; i < 5; i++) //for sorting nums
{
for (int j = i + 1; j < 5; j++)
{
if (num[i]>(num[j]))
{
int temp = num[i];
num[i] = num[j];
num[j] = temp;
}
}
}
for (int i = 0; i < 5; i++)// for sorting strs
{
for (int j = i + 1; j < 5; j++)
{
if (str[i].compareTo(str[j])>0)
{
String temp = str[i];
str[i] = str[j];
str[j] = temp;
}
}
}
System.out.println("The sorted strings are:");
for(int i=0; i<10; i++)//for merging both
{
if((i+1)%2==0)
{
int k=0;
str1[i]=String.valueOf(num[k]);
System.out.println("The String are "+str1[i]);
k++;
}
else
{
int j=0;
str1[i]=str[j];
System.out.println("The String are "+str1[i]);
j++;
}
}
/* for(int i=0; i<10; i++)
{
System.out.println("The String are "+str1[i]);
}
*/
}
}
我得到的输出:
The sorted strings are:
The String are ab
The String are 1
The String are ab
The String are 1
The String are ab
The String are 1
The String are ab
The String are 1
The String are ab
The String are 1
它只取两个数组的第一个元素。
最佳答案
您应该在循环之前将 k
和 j
初始化为 0
,而不是在循环内部。
int k=0;
int j=0;
for(int i=0; i<10; i++)//for merging both
{
if((i+1)%2==0)
{
str1[i]=String.valueOf(num[k]);
System.out.println("The String are "+str1[i]);
k++;
}
else
{
str1[i]=str[j];
System.out.println("The String are "+str1[i]);
j++;
}
}
关于java - 将一个 int 和 string 数组合并到第三个数组中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37993632/