java - 从数据库外的对象设置Choisebox的值属性

Question

如何设置对象的属性值以显示选择框？

@FXML
private ChoiceBox<LuggageBrand> brandSelector;

在这里您可以看到我用 LuggageBrand 对象填充选择框，但现在应用程序上显示的值是 .toString() 的对象。

我该怎么说，嘿，请使用此属性在选择框上显示？

Answer 1

在ChoiceBox上设置转换器:

public void initialize() {

    brandSelector.setConverter(new StringConverter<LuggageBrand>() {

        @Override
        public String toString(LuggageBrand luggageBrand) {
            // whatever logic you need here to turn the LuggageBrand object to a string:
            String value = luggageBrand.getXXX();
            return value ;
        }

        @Override
        public LuggageBrand fromString(String text) {
            // this method is not used by the ChoiceBox, so you can just
            return null ;
        }
    });

    // other initialization code...

}