java - 格式化为String()

Question

我是使用 toString() 方法返回格式化字符串的初学者。我正在打印一副纸牌，其中每一列都有不同的花色。有人有什么想法吗？这是我的代码:

public class DeckOfCards {
  public static void main(String[] args) {
    int[] deck = new int[52];
    //String[] suits = {"Spades", "Hearts", "Diamonds", "Clubs"};
    String[] suits = {"Clubs","Diamonds","Hearts","Spades"};
    //String[] ranks = {"Ace","King", "Queen", "Jack", "10", "9", "8", "7", "6", "5", "4", "3", "2"};
    String[] ranks = {"2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King","Ace"};


    // Initialize cards 
        for (int i = 0; i < deck.length; i++) {
            deck[i] = i;
        }

        // Shuffle the cards
        for (int i = 0; i < deck.length; i++) {
            int index = (int)(Math.random() * deck.length);
            int temp = deck[i];
            deck[i] = deck[index];
            deck[index] = temp;
        }

        // Display the all the cards
        for (int i = 0; i < 52; i++) {
            String suit = suits[deck[i] / 13];
            String rank = ranks[deck[i] % 13];
            System.out.println( rank + " of " + suit);
        }


        System.out.println("------------------------------");

        for(int i=0;i<deck.length;i++){
            for(int j=i;j<deck.length;j++){
                if(deck[j]==51-i){
                    int temp = deck[i];
                    deck[i] = deck[j];
                    deck[j] = temp;
                }
            }
        }

        // Display the all the cards
        for (int i = 0; i < 52; i++) {
            String suit = suits[deck[i] / 13];
            String rank = ranks[deck[i] % 13];
            System.out.printf( rank + " of " + suit + "\t");
        }

    }
  }

我相信 toString() 的主要区域在这里:

// Display the all the cards
        for (int i = 0; i < 52; i++) {
            String suit = suits[deck[i] / 13];
            String rank = ranks[deck[i] % 13];
            System.out.println( rank + " of " + suit);
        }

我如何在 toString() 方法中使用它并实例化一个可以打印此 toString() 方法的对象？感谢您的时间。为了让它在桥牌游戏中按顺序显示，我正在考虑这样的输出:

Ace of Spades     Ace of Hearts     Ace of Diamonds     Ace of Clubs
...
// And so on until it reaches two of clubs

这些方法中的任何一种都可以像这样打印它而不需要额外的空格吗？或者如果没有的话可以在 toString() 中修改什么来让它像这样打印出来？再次感谢您的宝贵时间。

Answer 1

您必须创建一个新的卡片类并拥有一个覆盖的字符串类

如下所示

public class Cards {

    private int numb;
    private int suite;

    public Cards(int suite, int numb) {
        this.numb = numb;
        this.suite = suite;
    }

    public int getNumb() {

        if (numb == 0){
            return 11;
        }

        if (numb >= 9 && numb <=12){
            return 10;
        }

        return numb + 1;
    }

    @Override
    public String toString() {

        String arbNumb = null;
        String arbSuite = null;

        switch (suite){

        case 0:
            arbSuite = "Heart";
            break;

        case 1:
            arbSuite = "Diamond";
            break;

        case 2:
            arbSuite = "Spades";
            break;

        case 3:
            arbSuite = "Clubs";
            break;

        }

        switch (numb){

        case 0:
            arbNumb = "Ace";
            break;

        case 10:
            arbNumb = "Jack";
            break;

        case 11:
            arbNumb = "Queen";
            break;

        case 12:
            arbNumb = "King";
            break;

        }

        if (numb > 0 && numb < 10){
            arbNumb = String.valueOf(numb+1);
        }

        return arbNumb + " of " + arbSuite;
    }

}

这意味着当你实例化Cards类时，当你调用yourInstanceOfClass.toString时，数字将被转换为相应的字符串。您可以对套房和号码进行此操作。

我分配的数字正是我的做法，但您当然可以根据自己的喜好更改它们。

getNumb() 类只是用来反射(reflect)我所做的数字的变化。