我正在开发一个项目,我必须从 Excel 文件中获取文件夹和子文件夹名称,保留层次结构并将它们存储在数组中,以使用该数组创建目录结构。
我正在使用 Apache POI 读取 Excel 文件。
考虑到我有 8 个树级别,如何将它们存储到数组中?
例如:
Folder
Subfolder01
Subfolder02
Subfolder02.01
Subfolder02.01.01
Subfolder02.01.01.01
Subfolder02.01.02
Subfolder03
Subfolder04
Subfolder04.01
Subfolder04.01.01
Subfolder04.01.01.01
Subfolder04.01.02
Subfolder04.01.02.01
Subfolder04.02
以下是我如何使用 Apache POI 库读取 excel 文件:
public class ExcelReadClass {
private static final String FILE_NAME = "D:/Work-Space/TESTExcel.xlsx";
public void readExcel(String fileName) {
try {
// XSSFWorkbook = XML SpreadSheet Format
// is for Excel 2007 or above
Workbook workbook = new XSSFWorkbook(fileName);
// Accessing the particular sheet
// here the parameter indicates the sheet number. 0 means first sheet, 1 means the second and so on
/// accessing first sheet - which is " Components "
Sheet sheet = workbook.getSheetAt(0);
/*
* Sheet can also be accessed using the sheet name like shown below
* Sheet sheet = workbook.getSheet("Components");
*/
// geting the rows
// following code will work with empty cells
Row row = null;
Cell cell = null;
// Returns: the number of physically defined rows in the selected sheet
//int noOfRows = sheet.getPhysicalNumberOfRows();
//Returns: last row contained n this sheet (0-based)
int noOfRows = sheet.getLastRowNum();
// starting from 0 - which is the first row
for(int i = 2; i <= noOfRows; i++) {
row = sheet.getRow(i);
//int noOfCells = row.getPhysicalNumberOfCells(); // returns the total number of cells in the selected row
//int noOfCells = row.getLastCellNum(); // returns the number of the last cell in the row
int noOfCells = 11;
这里我用Sysout输出文件结构 我必须将整个结构存储到数组中的地方
// starting from 0 - which is the first column ( aka cell )
for(int j = 1; j < noOfCells; j++) {
cell = row.getCell(j) ; // if there's no more cells, it returns null
if(cell != null ) {
System.out.print(getCellValue(cell) + "\t");
} else {
Cell blanckCell = row.createCell(j);
blanckCell.setCellValue("");
System.out.print(getCellValue(blanckCell) + "\t");
}
}
System.out.println();
}
workbook.close();
} catch (FileNotFoundException e) {
System.out.println("File is not available.");
e.printStackTrace();
} catch (IOException e) {
System.out.println("Problem reading file from directory.");
e.printStackTrace();
} catch (NullPointerException e){
System.err.println("Last part of Excel");
e.printStackTrace();
}
}
public Object getCellValue(Cell cell){
Object cellValue = null;
if(cell.getCellTypeEnum() == CellType.STRING){
cellValue = cell.getStringCellValue();
}else if(cell.getCellTypeEnum() == CellType.NUMERIC){
cellValue = cell.getNumericCellValue();
}else if(cell.getCellTypeEnum() == CellType.BOOLEAN){
cellValue = cell.getBooleanCellValue();
}else if(cell.getCellTypeEnum() == CellType.BLANK){
cellValue = "";
}
return cellValue;
}
}
最佳答案
这是一个可以帮助您开始的代码片段
try {
final String FILENAME = "c:\\Rest\\Test\\data.txt"; //change to your file location
BufferedReader br = new BufferedReader(new InputStreamReader(
new FileInputStream(FILENAME), "UTF-8")); //change it to your reader
String line;
//read file line by line
while ((line = br.readLine()) != null) {
System.out.println(line);
Node root = null;
if (line == "Folder") {
root = new Node(null);
} else {
String indexs = line.substring(9, line.length());
if (indexs.length() == 2) {
// insert to root
} else if (indexs.length() == 4) {
// create node and use readLine to all sub nodes
}
}
}
br.close();
} catch (IOException e) {
e.printStackTrace();
}
以及 Node
类:
import java.util.ArrayList;
import java.util.List;
public class Node {
private String id;
private final List<Node> children = new ArrayList<>();
private final Node parent;
public Node(Node parent) {
this.parent = parent;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public List<Node> getChildren() {
return children;
}
public Node getParent() {
return parent;
}
}
关于java - xlsx 文件的数据结构,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43864119/