java - 基于每个字母的 ASCII 值的句子中的平均单词值

Question

我想根据 ASCII 值计算每个单词的平均值 例如:你好，H= 72，e= 101，l= 108，l = 108，o = 111
求和得到 500，然后根据字母数计算平均值，即 500/5 =100 因此，Hello 的平均值 = 100，“World”的平均值相同，依此类推。 最后计算所有单词的平均值，将其相加并显示为整个句子的最终平均值 这是我创建的代码，但它在线程“main”java.lang.ArrayIndexOutOfBoundsException 中给出了异常

   import java.util.*;
   import java.lang.*;
   import java.io.*;
    class Word
    {
    public static void main (String[] args) 
    {

    String str="Hello World";
    int average1=0;
    int j=0;
    int[] average=new int[20];
    String[] s=str.split(" "); //Splitting into each word
    for(String s1 : s)
    {
    char[] c=s1.toCharArray();
    for(int i=0;i<str.length();i++)
    {
        average[i]=(int)c[i]; //Average ASCII based value for each word
    }
    while(average[j]!=0)
    {
    average1=average[j]/s1.length(); //Sum up average of each Word and average of who words is calculated 
    System.out.print(average1); 
    j++;
    }
    }
    }
    }

如果有人能帮我提供良好的逻辑，我将不胜感激。

Answer 1

实现这一目标的一个简单方法是执行以下操作:

public class WordAverage{
   public static void main (String[] args) {

       String str="Hello World"; 
       double average=0; // you need only one double variable, why double -> because of the division later 
        // note that if you don't want the decimal you can change it to int
        for(char c : str.toCharArray()){ // cycle through every char in the String
            if(c!=' '){ // if it is not a space
               average += (int)c; // sum its value
            }
        }

       average /= str.replace(" ", "").length(); // then divide the average value by the String length after removing the spaces (if any)
        System.out.println(average);
    }
  }

测试

Hello World     -> 102.0
How Are You?    -> 96.2
Fine Thank You! -> 95.23