无法弄清楚为什么下面的代码中的编码对象为空。您能指出我缺少什么吗?
还有一个问题:
setStaffList(List<Staff> staffList)
中是否需要运行for循环在职员类。我对这一点有点困惑。
xml:
<?xml version="1.0"?>
<company>
<staff id="1001">
<firstname>YW</firstname>
<lastname>mook kim</lastname>
<nickname>mkyong</nickname>
<salary>100000</salary>
</staff>
<staff id="2001">
<firstname>low</firstname>
<lastname>yin fong</lastname>
<nickname>fong fong</nickname>
<salary>200000</salary>
</staff>
</company>
解码代码:
public class XmlToList {
public static void main(String[] args) {
File xmlFile = new File("D:/CoreJavaPractice/XMLCode/src/staff.xml");
JAXBContext jaxbContext;
Company comp;
try {
jaxbContext = JAXBContext.newInstance(Company.class);
comp = (Company) jaxbContext.createUnmarshaller().unmarshal(xmlFile);
System.out.println(comp + "; " + xmlFile);
List<Staff> staffList = comp.getStaffList();
System.out.println(staffList);
for (Staff s : staffList) {
System.out.println(s.getFirstname());
}
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
公司类别:
@XmlRootElement(name = "company")
public class Company {
List<Staff> staffList;
public Company() {
}
public Company(List<Staff> staffList) {
this.staffList = staffList;
}
public List<Staff> getStaffList() {
return staffList;
}
public void setStaffList(List<Staff> staffList) {
/*
* for (Staff s : staffList) { this.staffList.add(s); }
*/
this.staffList = staffList;
}
}
员工等级:
@XmlRootElement(name = "staff")
public class Staff {
Integer id;
String firstname;
String lastname;
String nickname;
String salary;
public Staff() {
}
public Staff(Integer id, String firstname, String lastname, String nickname, String salary) {
super();
this.id = id;
this.firstname = firstname;
this.lastname = lastname;
this.nickname = nickname;
this.salary = salary;
}
public Integer getId() {
return id;
}
@XmlAttribute
public void setId(Integer id) {
this.id = id;
}
public String getFirstname() {
return firstname;
}
@XmlElement
public void setFirstname(String firstname) {
this.firstname = firstname;
}
public String getLastname() {
return lastname;
}
@XmlElement
public void setLasttname(String lasttname) {
this.lastname = lasttname;
}
public String getNickname() {
return nickname;
}
@XmlElement
public void setNickname(String nickName) {
this.nickname = nickName;
}
public String getSalary() {
return salary;
}
@XmlElement
public void setSalary(String salary) {
this.salary = salary;
}
}
最佳答案
建议您显式设置XmlAccessorType
和XmlElement
,这样您的Company类将是:
@XmlRootElement(name = "company")
@XmlAccessorType(XmlAccessType.PROPERTY)
public class Company {
private List<Staff> staffList;
public Company() {
}
public Company(List<Staff> staffList) {
this.staffList = staffList;
}
public List<Staff> getStaffList() {
return staffList;
}
@XmlElement(name = "staff")
public void setStaffList(List<Staff> staffList) {
this.staffList = staffList;
}
}
关于java - 使用 JAXB 解码在下面的代码中给出 null 吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47364517/