我在使用此 try/catch 语句时遇到问题。我试图用它来抛出一条错误消息:“请输入一个整数!”如果用户输入一个字母。我使用的第一个有效,但它最终需要两行用户输入而不是一行,所以它基本上跳过了一个应该问的问题。之后,其他的都不起作用,它们只是被完全跳过。我还需要对用户输入做同样的事情,如果用户在应该是字母的地方输入整数,它会抛出一条错误消息,提示“请输入字符串!”。我知道我已经很接近了!
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
boolean validInput = false;
int val = 0;
System.out.print("Enter your first name: ");
String firstName = input.nextLine();
System.out.print("Enter your last name: ");
String lastName = input.nextLine();
System.out.print("Enter your address: ");
String address = input.nextLine();
System.out.print("Enter your city: ");
String city = input.nextLine();
System.out.print("Enter your state: ");
String state = input.nextLine();
System.out.print("Enter your zip code + 4: ");
String zip = input.nextLine();
while(!validInput) {
try {
val = input.nextInt();
validInput = true;
} catch(Exception e) {
System.out.println("Please enter an integer!");
input.nextLine();
}
}
System.out.print("Enter amount owed: ");
String amount = input.nextLine();
while(!validInput) {
try {
val = input.nextInt();
validInput = true;
} catch(Exception e) {
System.out.println("Please enter an integer!");
input.next();
}
}
System.out.print("Enter your payment amount: ");
String payment = input.nextLine();
while(!validInput) {
try {
val = input.nextInt();
validInput = true;
} catch(Exception e) {
System.out.println("Please enter an integer!");
input.next();
}
}
System.out.print("Enter the date of payment: ");
String date = input.nextLine();
while(!validInput) {
try {
val = input.nextInt();
validInput = true;
} catch(Exception e) {
System.out.println("Please enter an integer!");
input.next();
}
}
System.out.println("\t\t\t\t\t" + "XYZ Hospital");
System.out.println();
System.out.println("Name Information" + "\t\t\t\t" + "Address" + "\t\t\t\t\t\t" + "Payment");
System.out.println();
System.out.println("Last" +"\t"+ "First" + "\t\t\t" + "Address Line 1" + "\t" + "City" + "\t" + "State" + "\t" + "Zip" + "\t" + "Amount Owed" + "\t" + "Payment Amount" + "\t" + "Payment Date");
System.out.println();
System.out.println(lastName + " " + firstName + "\t" + address + " " + city + ", " + state + " " + zip + "\t" + amount + "\t\t" + payment +"\t\t"+ date);
System.out.print("Would you like to enter abother patient? Type Yes or No: ");
String userInput = input.nextLine();
if (userInput.equals("Yes")) {
while (userInput.equals("Yes")) {
System.out.print("Enter your first name: ");
String firstName2 = input.nextLine();
System.out.print("Enter your last name: ");
String lastName2 = input.nextLine();
System.out.print("Enter your address: ");
String address2 = input.nextLine();
System.out.print("Enter your city: ");
String city2 = input.nextLine();
System.out.print("Enter your state: ");
String state2 = input.nextLine();
System.out.print("Enter your zip code + 4: ");
String zip2 = input.nextLine();
System.out.print("Enter amount owed: ");
String amount2 = input.nextLine();
System.out.print("Enter your payment amount: ");
String payment2 = input.nextLine();
System.out.print("Enter the date of payment: ");
String date2 = input.nextLine();
System.out.println("\t\t\t\t\t" + "XYZ Hospital");
System.out.println();
System.out.println("Name Information" + "\t\t\t\t" + "Address" + "\t\t\t\t\t\t" + "Payment");
System.out.println();
System.out.println("Last" +"\t"+ "First" + "\t\t\t" + "Address Line 1" + "\t" + "City" + "\t" + "State" + "\t" + "Zip" + "\t" + "Amount Owed" + "\t" + "Payment Amount" + "\t" + "Payment Date");
System.out.println();
System.out.println(lastName2 + " " + firstName2 + "\t" + address2 + " " + city2 + ", " + state2 + " " + zip2 + "\t" + amount2 + "\t\t" + payment2 +"\t\t"+ date2);
System.out.print("Would you like to enter another patient? Type Yes or No: ");
userInput = input.nextLine();
}
}
else if (userInput.equals("No")) {
System.out.println("Goodbye");
}
最佳答案
在第一个 while 循环之后,您不会将 validInput 重置为 False。所以就不进入下一个了。
关于java - java try/catch 的问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48844244/