java - 如何在Java中解析具有混合节点和文本的XML？

Question

我有一个格式为 xml -

<root>
      <sentence>
           first part of the text 

           <a id="interpolation_1"> </a>

           second part of the text

           <a id="interpolation_2"> </a>
      </sentence>
</root>

本质上，<sentence>标签代表一个句子，子标签<a>是句子中的插值部分。

XPath 表达式 String sentence = xPath.evaluate("sentence", transUnitElement);将文本指定为 - first part of the text second part of the text即它省略了插值。

XPath 表达式 -

NodeList aList = (NodeList) xPath.evaluate("/sentence/a", transUnitElement, XPathConstants.NODESET);给出 <a> 的列表元素。

如何解析它们以获取 <sentence> 的文本元素以及 <a>元素不丢失 <a> 的顺序和位置元素？

预期输出 - the first part of the sentence {interpolation_1} second part of the text {interpolation_2}

Answer 1

您正在寻找的结果可以通过迭代sentence的子节点并逐步构建目标字符串来实现。例如:

// retrieve <sentence> as Node, not as text
Node sentence = (Node) xPath.evaluate("sentence", transUnitElement, XPathConstants.NODE);

StringBuilder resultBuilder = new StringBuilder();
NodeList children = sentence.getChildNodes();

for (int i = 0; i < children.getLength(); i++) {
  Node child = children.item(i);
  short nodeType = child.getNodeType();
  switch (nodeType) {
    case Node.TEXT_NODE:
      String text = child.getTextContent().trim();
      resultBuilder.append(text);
      break;
    case Node.ELEMENT_NODE:
      String id = ((Element) child).getAttribute("id");
      resultBuilder.append(" {").append(id).append("} ");
      break;
    default:
      throw new IllegalStateException("Unexpected node type: " + nodeType);
  }
}
// outputs "first part of the text {interpolation_1} second part of the text {interpolation_2}"
System.out.println(resultBuilder.toString());