Spring 启动 2.0.0.RELEASE
我有属性类:
@Configuration
@ConfigurationProperties(prefix="person")
public class PersonProperties {
private AddressProperties addressProperties;
public AddressProperties getAddressProperties() {
return addressProperties;
}
public void setAddressProperties(final AddressProperties addressProperties) {
this.addressProperties = addressProperties;
}
public static class AddressProperties {
private String line1;
public String getLine1() {
return line1;
}
public void setLine1(final String line1) {
this.line1 = line1;
}
}
}
和application.yml
:
person:
address:
line1: line1OfAddress
它没有正确绑定(bind),因为我的 AddressProperties
对象是 null
。
当类与 yml 属性 AddressProperties
-> Address
具有相同名称时,它可以正常工作。我尝试添加带有前缀 address
的 Qualifier
或 ConfigurationProperties
但它不起作用。不幸的是,我在 spring 文档中找不到有关此案例的有用信息。
如何为嵌套属性指定前缀?
最佳答案
yaml/属性文件中定义的属性应与类中定义的变量匹配。 将 yaml 文件更改为
person:
# addressProperties will also work here
address-properties:
line1: line1OfAddress
或者将你的bean定义为
@Configuration
@ConfigurationProperties(prefix = "person")
public class PersonProperties {
// here variable name doesn't matter, it can be addressProperties as well
// setter / getter should match with properties in yaml
// i.e. getAddress() and setAddress()
private AddressProperties address;
public AddressProperties getAddress() {
return address;
}
public void setAddress(AddressProperties address) {
this.address = address;
}
}
如果您想获取地址下的所有属性而不在单独的 bean 中定义它们,您可以将 PersonProperties
类定义为
@Configuration
@ConfigurationProperties(prefix = "person")
public class PersonProperties {
private Map<String, Object> address;
public Map<String, Object> getAddress() {
return address;
}
public void setAddress(Map<String, Object> address) {
this.address = address;
}
}
这里PersonProperties#address
将包含{line1=line1OfAddress}
现在,地址下的所有属性都将位于 map
中。
关于java - spring中嵌套配置属性的前缀,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50345888/