我正在制作一个 GUI，在其中将字符串输入到文本框中，一旦单击 J 按钮，第二个文本框将生成我在第一个文本框中输入的字符串，或者从我创建的方法(public void Associate())。当我运行 GUI 并单击按钮在第二个文本框中生成文本时，一切正常。但是，当我第二次单击该按钮以使 GUI 执行相同的操作时，什么也没有发生。我可以做些什么，这样我就不必每次想多次运行 GUI 时都关闭它？
public class GUIWindow extends JFrame {
private Joketeller robot= new Joketeller();
private JLabel speakerlabel = new JLabel("Joke");
private JLabel MarcoLabel= new JLabel ("Marco");
private JTextField speakerfield= new JTextField ("Enter Joke Here");
private JTextField Marcofield= new JTextField ("",20);
private JButton Jokebutton=new JButton("Recite Joke >>>");
public GUIWindow() {
JPanel dataPanel= new JPanel(new GridLayout(2,2,12,16));
dataPanel.add(speakerlabel);
dataPanel.add(MarcoLabel);
dataPanel.add(speakerfield);
dataPanel.add(Marcofield);
JPanel buttonPanel= new JPanel();
buttonPanel.add(Jokebutton);
Container container = getContentPane();
container.add(dataPanel,BorderLayout.CENTER);
container.add(buttonPanel,BorderLayout.SOUTH);
Jokebutton.addActionListener(new JokeListener());
}
private class JokeListener implements ActionListener {
public void actionPerformed(ActionEvent e) {
String input=speakerfield.getText();
if (Jokebutton.isEnabled()) {
robot.setJoke(input);
String Response= robot.getResponse();
Marcofield.setText(Response);}
说笑者类:
public class Joketeller {
private static String Marco;
private static String Response;
static int i= (int)(Math.random()*((5-1)+1)+1);
static String r;
public void setMarco(String Joke ) {
Marco=Joke;
}
public void setJoke(String Joke) {
Marco=Joke;
associate();
}
public String getJoke() {
return Marco;
}
public static String getMarco() {
return Marco;
}
public static void associate(){
if(i==1)
r= "Connect Angie";
else if(i==2)
r= "*Cloud Laugh*";
else if(i==3)
r= "Community";
else if(i==4)
r=getMarco();
else if(i==5)
r= "Indeed!";
Response=r;
}
public String getResponse() {
return Response;
}
}
感谢任何帮助。谢谢。
最佳答案
我首先想到的是过度使用static...
public class Joketeller {
private static String Marco;
private static String Response;
static int i= (int)(Math.random()*((5-1)+1)+1);
static String r;
这对您没有帮助，如果做得正确，则不需要。
下一期是关于i...
static int i = (int) (Math.random() * ((5 - 1) + 1) + 1);
public static void associate() {
if (i == 1) {
r = "Connect Angie";
} else if (i == 2) {
r = "*Cloud Laugh*";
} else if (i == 3) {
r = "Community";
} else if (i == 4) {
r = getMarco();
} else if (i == 5) {
r = "Indeed!";
}
Response = r;
}
i 从未改变。因为它是静态，所以您可以根据需要创建任意数量的 Joketeller 实例，并且需要更改它，因此响应将始终相同。
虽然有多种可能的方法来修复它，但最简单的方法是删除所有 static 并使 i 成为 associate< 中的局部变量，因为它确实没有在其他地方使用过..
public void associate() {
int rnd = (int) (Math.random() * ((5 - 1) + 1) + 1);
if (rnd == 1) {
r = "Connect Angie";
} else if (rnd == 2) {
r = "*Cloud Laugh*";
} else if (rnd == 3) {
r = "Community";
} else if (rnd == 4) {
r = getMarco();
} else if (rnd == 5) {
r = "Indeed!";
}
response = r;
}
这意味着您无需创建 Joketeller 的新实例即可获得不同的响应。
例如......
import java.awt.BorderLayout;
import java.awt.Container;
import java.awt.EventQueue;
import java.awt.GridLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JTextField;
public class GUIWindow extends JFrame {
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
GUIWindow wnd = new GUIWindow();
wnd.pack();
wnd.setLocationRelativeTo(null);
wnd.setVisible(true);
}
});
}
private Joketeller robot = new Joketeller();
private JLabel speakerlabel = new JLabel("Joke");
private JLabel marcoLabel = new JLabel("Marco");
private JTextField speakerfield = new JTextField("Enter Joke Here");
private JTextField marcofield = new JTextField("", 20);
private JButton jokebutton = new JButton("Recite Joke >>>");
public GUIWindow() {
JPanel dataPanel = new JPanel(new GridLayout(2, 2, 12, 16));
dataPanel.add(speakerlabel);
dataPanel.add(marcoLabel);
dataPanel.add(speakerfield);
dataPanel.add(marcofield);
JPanel buttonPanel = new JPanel();
buttonPanel.add(jokebutton);
Container container = getContentPane();
container.add(dataPanel, BorderLayout.CENTER);
container.add(buttonPanel, BorderLayout.SOUTH);
jokebutton.addActionListener(new JokeListener());
}
private class JokeListener implements ActionListener {
public void actionPerformed(ActionEvent e) {
String input = speakerfield.getText();
if (jokebutton.isEnabled()) {
robot.setJoke(input);
String Response = robot.getResponse();
marcofield.setText(Response);
}
}
}
public class Joketeller {
private String marco;
private String response;
private String r;
public void setMarco(String Joke) {
marco = Joke;
}
public void setJoke(String Joke) {
marco = Joke;
associate();
}
public String getJoke() {
return marco;
}
public String getMarco() {
return marco;
}
public void associate() {
int rnd = (int) (Math.random() * ((5 - 1) + 1) + 1);
if (rnd == 1) {
r = "Connect Angie";
} else if (rnd == 2) {
r = "*Cloud Laugh*";
} else if (rnd == 3) {
r = "Community";
} else if (rnd == 4) {
r = getMarco();
} else if (rnd == 5) {
r = "Indeed!";
}
response = r;
}
public String getResponse() {
return response;
}
}
}
关于java - 多次运行 GUI 客户端而无需关闭它，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/53875639/