我已经制作了一些人类对象,我通过使用 ObserveableList 打印它们的变量属性并在初始化方法中调用它,问题是我不明白如何单独打印每个对象,这些是作为整体打印的我想要逐一迭代
Person p1 = new Person("1001", "person1", "11");
Person p2 = new Person("1002", "person2", "12");
Person p3 = new Person("1003", "person3", "13");
Person p4 = new Person("1004", "person4", "14");
ObservableList<Person> personDataTable = FXCollections.observableArrayList(p1, p2, p3, p4);
@Override
public void initialize(URL location, ResourceBundle resources) {
printTable();
}
public void printTable() {
tableID.setCellValueFactory(new PropertyValueFactory<Person, String>("id"));
tableName.setCellValueFactory(new PropertyValueFactory<Person, String>("name"));
tableAge.setCellValueFactory(new PropertyValueFactory<Person, String>("age"));
tableView.setItems(personDataTable);
}
澄清一下,您想要将一个人添加到表中,稍等一下,添加下一个人,再等一秒,添加下一个人,依此类推,对吗? 是的,完全正确(我无法回复评论)
最佳答案
关键是Timeline
。基本上,使用计数器并确保当计数器大于或等于保存人员对象的列表的大小时停止时间线。 MCVE如下:
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.atomic.AtomicInteger;
import javafx.animation.KeyFrame;
import javafx.animation.Timeline;
import javafx.application.Application;
import javafx.collections.FXCollections;
import javafx.collections.ObservableList;
import javafx.scene.Scene;
import javafx.scene.control.TableColumn;
import javafx.scene.control.TableView;
import javafx.scene.control.cell.PropertyValueFactory;
import javafx.scene.layout.StackPane;
import javafx.stage.Stage;
import javafx.util.Duration;
/**
*
* @author Sedrick
*/
public class JavaFXApplication86 extends Application {
Timeline timeline;
AtomicInteger counter;
@Override
public void start(Stage primaryStage) {
Person p1 = new Person("1001", "person1", "11");
Person p2 = new Person("1002", "person2", "12");
Person p3 = new Person("1003", "person3", "13");
Person p4 = new Person("1004", "person4", "14");
List<Person> personList = new ArrayList();
personList.add(p1);
personList.add(p2);
personList.add(p3);
personList.add(p4);
counter = new AtomicInteger();
TableView<Person> tableView = new TableView();
TableColumn<Person, String> tableId = new TableColumn("ID");
TableColumn<Person, String> tableName = new TableColumn("Name");
TableColumn<Person, String> tableAge = new TableColumn("Age");
ObservableList<Person> personDataTable = FXCollections.observableArrayList();
tableView.setItems(personDataTable);
tableId.setCellValueFactory(new PropertyValueFactory("id"));
tableName.setCellValueFactory(new PropertyValueFactory("name"));
tableAge.setCellValueFactory(new PropertyValueFactory("age"));
timeline = new Timeline(new KeyFrame(Duration.seconds(1), event ->{
if(counter.get() >= personList.size())
{
timeline.stop();
}else{
personDataTable.add(personList.get(counter.getAndIncrement()));
}
}));
timeline.setCycleCount(Timeline.INDEFINITE);
timeline.play();
tableView.getColumns().addAll(tableId, tableName, tableAge);
StackPane root = new StackPane(tableView);
Scene scene = new Scene(root, 300, 250);
primaryStage.setTitle("Hello World!");
primaryStage.setScene(scene);
primaryStage.show();
}
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
launch(args);
}
}
关于java - 有什么方法可以迭代打印(或在一秒后)tableView(javaFX)中的表记录,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55669503/