我收到“QueryException:JPA 样式位置参数不是整数序数” 我尝试用其他人解决的方式来解决,例如 org.hibernate.QueryException: JPA-style positional param was not an integral ordinal但还是不行。
我尝试将更改形式 ?1 硬编码为数据库中已有的某些数据,它可以工作,但更改为 ?1 后,它再次出现错误。
--- 硬编码之前(有错误) -- 在存储库中 --
@Query(
value = "SELECT user_att_workshop.id, user_att_workshop.user_id, user_att_workshop.workshop_att_id, skill.skill_name, user_att_workshop.skill_score " +
"FROM user_att_workshop LEFT JOIN skill on user_att_workshop.skill_id = skill.id " +
"WHERE user_att_workshop.user_id = ?1 " +
"AND user_att_workshop.workshop_att_id = ?2;",
nativeQuery = true
)
public List<UserScoreByWorkshopAtt> findUserScoreByUserIdAndWorkshopId(int userId, int workshopId);
-- 服务中 --
public List<UserScoreByWorkshopAtt> findUserScoreByUserIdAndWorkshopIdtest(
int userId,
int workshopId) {
return
userScoreByWorkshopAttRepository.findUserScoreByUserIdAndWorkshopId(
userId,
workshopId
);
}
-- 在 Controller 中 --
List<UserScoreByWorkshopAtt> getUserScooreByUserId(
@PathVariable("user_id") int userId,
@PathVariable("workshop_id") int workshopId) {
return userScoreByWorkshopAttService.findUserScoreByUserIdAndWorkshopIdtest(
userId,
workshopId
);
}
--- 硬编码后(可以运行并且没有错误) -- 在存储库中 --
@Query(value = "SELECT user_att_workshop.id, user_att_workshop.user_id, user_att_workshop.workshop_att_id, skill.skill_name, user_att_workshop.skill_score FROM user_att_workshop LEFT JOIN skill on user_att_workshop.skill_id = skill.id WHERE user_att_workshop.user_id = 5 AND user_att_workshop.workshop_att_id = 2;", nativeQuery = true)
public List<UserScoreByWorkshopAtt> findUserScoreByUserIdAndWorkshopId();
-- 服务中 --
public List<UserScoreByWorkshopAtt> findUserScoreByUserIdAndWorkshopIdtest() {
return userScoreByWorkshopAttRepository.findUserScoreByUserIdAndWorkshopId();
}
-- 在 Controller 中 --
List<UserScoreByWorkshopAtt> getUserScooreByUserId(@PathVariable("user_id") int userId,
@PathVariable("workshop_id") int workshopId) {
return userScoreByWorkshopAttService.findUserScoreByUserIdAndWorkshopIdtest();
}
Caused by: org.hibernate.QueryException: JPA-style positional param was not an integral ordinal at org.hibernate.engine.query.spi.ParameterParser.parse(ParameterParser.java:195) at org.hibernate.engine.query.spi.ParamLocationRecognizer.parseLocations(ParamLocationRecognizer.java:56) at org.hibernate.engine.query.internal.NativeQueryInterpreterStandardImpl.getParameterMetadata(NativeQueryInterpreterStandardImpl.java:30) at org.hibernate.engine.query.spi.QueryPlanCache.getSQLParameterMetadata(QueryPlanCache.java:128) at org.hibernate.internal.AbstractSharedSessionContract.getNativeQueryImplementor(AbstractSharedSessionContract.java:1000) ... 85 more
最佳答案
你可以这样写吗:
@Query(
value = "SELECT user_att_workshop.id, user_att_workshop.user_id, user_att_workshop.workshop_att_id, skill.skill_name, user_att_workshop.skill_score " +
"FROM user_att_workshop LEFT JOIN skill on user_att_workshop.skill_id = skill.id " +
"WHERE user_att_workshop.user_id = :userId " +
"AND user_att_workshop.workshop_att_id = :workshopId;",
nativeQuery = true
)
public List<UserScoreByWorkshopAtt> findUserScoreByUserIdAndWorkshopId(@Param("userId")int userId,@Param("workshopId") int workshopId);
或者从查询末尾删除 ';'
并检查是否有空格
@Query(
value = "SELECT user_att_workshop.id, user_att_workshop.user_id, user_att_workshop.workshop_att_id, skill.skill_name, user_att_workshop.skill_score " +
"FROM user_att_workshop LEFT JOIN skill on user_att_workshop.skill_id = skill.id " +
"WHERE user_att_workshop.user_id =?1 " +
"AND user_att_workshop.workshop_att_id =?2",
nativeQuery = true
)
public List<UserScoreByWorkshopAtt> findUserScoreByUserIdAndWorkshopId(int userId, int workshopId);
关于java - 查询异常 : JPA-style positional param was not an integral ordinal,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56310935/