我想要匹配以下内容:零长度的行，匹配继续跨越非零长度的行，直到在行中匹配特定字符串。例如:比赛从零长度线开始，一直持续到到达 STOP:
Some random text I don't care about
The match starts at the beginning of this line
The match continues across this line
The match stops here STOP more
text I don't care about
有什么建议吗？
谢谢
最佳答案
这应该可以做到:
(?ms)^[ \t]*+$\s*+((?:(?!STOP).)*+)
一个小演示:
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Main {
public static void main(String[] args) {
String text = "Some random text I don't care about" + "\n" +
"" + "\n" +
"The match starts at the beginning of this line" + "\n" +
"The match continues across this line" + "\n" +
"The match stops here STOP more" + "\n" +
"don't care about" + "\n" +
"" + "\n" +
"" + "\n" +
"" + "\n" +
"foo" + "\n" +
"barSTOP" + "\n" +
"text I don't care about";
Matcher m = Pattern.compile("(?ms)^[ \t]*+$\\s*+(?:(?!STOP).)*+").matcher(text);
while(m.find()) {
System.out.println("match ->"+m.group()+"<-");
}
}
}
将输出:
match ->
The match starts at the beginning of this line
The match continues across this line
The match stops here <-
match ->
foo
bar<-
一个小解释:
(?ms) # enable mutli-line and dot-all
^[ \t]*+$ # match and empty line
\s*+ # match the line break
( # start group 1
(?:(?!STOP).) # if the string 'STOP' cannot be seen, match any character
*+ # match the previous zero or more times (possessively)
) # stop group 1
关于java - Java 中的正则表达式以零长度行开始并跨行继续，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/1728754/