有谁知道我可以使用 PHP 从 MySql DB 中的 2 个表获取数据的方法吗？我的 Android 应用程序允许用户将商品放入购物车(MySql 中的表)。当用户单击应用程序中的购物车按钮时，它会加载“购物车 Activity ”，并根据“ session ID”或“客户 ID”加载 ListView ，其中包含他们添加到购物车的所有内容(如果用户已登录) .我现在要做的就是当商品添加到购物车时，我捕获产品 ID、产品名称、图像 URL、数量和价格。它效果很好而且很快。我想要做的是，由于产品名称、图像 url 和价格已经在“产品表”中，所以我想做同样的事情，但是当用户将商品添加到购物车时，仅捕获产品 ID 和 session ID 。当客户进入购物车 Activity 时，我希望我的 PHP 脚本获取 Shopping_Cart 表中的产品 ID，然后在产品表中搜索该产品 ID 并返回价格、图像 URL、名称等。
这是我的 PHP 脚本:
if($The_Function=="LOAD_CART"){
$response = array();
require_once __DIR__ . '/db_connect.php';
$con = new DB_CONNECT();
$user_session = $_GET['session'];
$user_item_status = $_GET['status'];
$order_total = 0.00;
$result = mysql_query("SELECT * FROM shopping_cart WHERE SessionID LIKE '$user_session' AND Status LIKE '$user_item_status'");
if(!empty($result)){
if (mysql_num_rows($result) > 0) {
$response["cart_contents"] = array();
//$result = mysql_fetch_array($result);
while ($row = mysql_fetch_array($result)) {
$myItems = array();
$myItems["product_id"] = $row["PID"];
$myItems["product_name"] = $row["Item"];
$myItems["product_price"] = $row["Price"];
$myItems["product_qty"] = $row["Qty"];
$myItems["image_url"] = $row["URL"];
$myItems["line_id"] = $row["ItemCount"];
$line_total = $row["Price"] * $row["Qty"];
$order_total = $order_total + $line_total;
array_push($response["cart_contents"], $myItems);
}
// success
$response["success"] = 1;
$response["order_total"] = $order_total;
// user node
// $response["products"] = array();
// echoing JSON response
echo json_encode($response);
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
}
这就是我正在尝试做的事情。此代码不起作用。
if($The_Function=="LOAD_CART2"){
$response = array();
require_once __DIR__ . '/db_connect.php';
$con = new DB_CONNECT();
$user_session = $_GET['session'];
$user_item_status = $_GET['status'];
$order_total = 0.00;
$result = mysql_query("SELECT * FROM shopping_cart WHERE SessionID LIKE '$user_session' AND Status LIKE '$user_item_status'");
if(!empty($result)){
if (mysql_num_rows($result) > 0) {
$response["cart_contents"] = array();
//$result = mysql_fetch_array($result);
while ($row = mysql_fetch_array($result)) {
$line_total = $row["Price"] * $row["Qty"];
$line_ID = $row["ItemCount"];
$Quantity = $row["Qty"];
$Prod_ID = $row["PID"];
$result2 = mysql_query("SELECT * FROM products WHERE pid LIKE '$Prod_ID'");
$myItems = array();
$theItem=$row["name"];
$thePrice=$row["price"];
$theImage=$row["prod_image"];
$myItems["line_id"] = $line_ID;
$myItems["product_qty"] = $Quantity;
$myItems["product_id"] = $Prod_ID;
$myItems["product_name"] = $theItem;
$myItems["product_price"] = $thePrice;
$myItems["image_url"] = $theImage;
$order_total = $order_total + $line_total;
array_push($response["cart_contents"], $myItems);
}
}
// success
$response["success"] = 1;
$response["order_total"] = $order_total;
// user node
// $response["products"] = array();
// echoing JSON response
echo json_encode($response);
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
这就是我刚刚尝试过的:
if($The_Function=="LOAD_CART2"){
$response = array();
require_once __DIR__ . '/db_connect.php';
$con = new DB_CONNECT();
$user_session = $_GET['session'];
$user_item_status = $_GET['status'];
$order_total = 0.00;
$result = mysql_query("SELECT s.*, p.* FROM shopping_cart AS s LEFT JOIN products AS p ON p.pid = s.PID WHERE s.SessionID ='$user_session' AND s.Status = '$user_item_status'");
if(!empty($result)){
if (mysql_num_rows($result) > 0) {
$response["cart_contents"] = array();
//$result = mysql_fetch_array($result);
while ($row = mysql_fetch_array($result)) {
$myItems = array();
//FROM shopping_cart Table
$line_total = $row["Price"] * $row["Qty"];
$myItems["line_id"] = $row["ItemCount"];
$myItems["product_qty"] = $row["Qty"];
$myItems["product_id"] = $row["PID"];
//FROM product TABLE
$myItems["product_name"]=$row["p.name"];
$myItems["product_price"]=$row["p.price"];
$myItems["image_url"]=$row["p.prod_image"];
}
$order_total = $order_total + $line_total;
array_push($response["cart_contents"], $myItems);
}
// success
$response["success"] = 1;
$response["order_total"] = $order_total;
// user node
// $response["products"] = array();
// echoing JSON response
echo json_encode($response);
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
} else {
// no product found
$response["success"] = 0;
$response["message"] = "No product found";
// echo no users JSON
echo json_encode($response);
}
我的方案:
products TABLE
pid|name|price|created_at|prod_image|description|catagory
shopping_cart TABLE
FirstName|LastName|OrderNumber|CustomerID|Email|Price|Qty|Status|URL|PID|SessionID|CustomerType|ItemCount
最佳答案
您应该使用 LEFT JOIN，而不是对每个项目进行单独的查询。
类似于:
“从 Shopping_cart AS 中选择 s.*, p.*
LEFT JOIN 产品 AS p ON p.pid = s.PID
WHERE s.SessionID ='$user_session' AND s.Status ='$user_item_status'
假设小写的pid在products表中，大写的pid在shopping_card表中。
关于php - 从 2 个表中检索数据 PHP、MySql、Android，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/17498593/