我已经开发了一些代码来更新mysql数据库中的字段,但是它根本无法正常工作。这是我的代码:
$note = mysqli_real_escape_string($con, $_REQUEST["note"]);
$read_note_sql = "UPDATE notes SET read = 'Y' WHERE id = '$note'";
$read_note_res = mysqli_query($con, $read_note_sql) or die(mysqli_error());
if(mysqli_affected_rows($con)>0){
echo "1";
}
else
{
echo "0";
}
这回显0,并显示错误“ mysqli_error()恰好期望1个参数,给定0”
谁能告诉我这里有什么解决方案?谢谢
最佳答案
查看是否可行:
$note = mysqli_real_escape_string($con, $_REQUEST['note']);
$read_note_sql = "UPDATE notes SET read = 'Y' WHERE id = '$note'";
if (!mysqli_query($con, $read_note_sql)) {
printf("Errormessage: %s\n", mysqli_error($con));
}
else {
// printf("Affected rows (UPDATE): %d\n", mysqli_affected_rows($con));
if(mysqli_affected_rows($con)>0){
echo "1";
}
else
{
echo "0";
}
}
关于php - PHP更新表错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17862251/