我想知道如何在不刷新页面的情况下选择复选框中的值
<div class="da-form-row">
<label>Filter</label>
<div class="da-form-item">
<ul class="da-form-list inline">
<span class="formNote">
<?= $_LANG[211]; ?>
</span>
<li>
<input class="uniform" type="checkbox" name="individual" id="individual" value="0" />
<label>
<?= $_LANG[11]; ?>
</label>
</li>
<li>
<input class="uniform" type="checkbox" name="individual" id="individual" value="1" />
<label>
<?= $_LANG[12]; ?>
</label>
</li>
<li>
<input class="uniform" type="checkbox" name="individual" id="individual" value="2" />
<label>
<?= $_LANG[13]; ?>
</label>
</li>
<li>
<input class="uniform" type="checkbox" name="individual" id="individual" value="3" />
<label>
<?= $_LANG[14]; ?>
</label>
</li>
</ul>
</div>
</div>
<div class="da-form-row">
<label>
<?= $_LANG[134];?>
<span class="required">*</span></label>
<div class="da-form-item large"> <span class="formNote">
<?= $_LANG[135];?>
</span>
<select class="chzn-select required" name="ano_letivo">
<?
$type = $_GET['filter'];
$q
->select()
->from('user')
->where_equal_to(
array(
'cargo'=>$type
)
)
->run();
if($q){
$unit=$q->get_selected();
foreach($unit as $array){
print "<option value='".$array['id']."'>".$array['nome']."</option>";
}
}
?>
</select>
</div>
</div>
我想要不刷新页面。 通过ajax我该怎么做？
记住，如果也选择了 4 个过滤器，则有 4 个复选框。
->where_equal_to(
array(
'cargo'=>$type,
'cargo'=>$type2,
'cargo'=>$type3
)
)
最佳答案
试试这个代码。单击每个复选框，ajax 查询将传递到您的服务器端
<div class="da-form-row">
<label>Filter</label>
<div class="da-form-item">
<ul class="da-form-list inline">
<span class="formNote">
<?= $_LANG[211]; ?>
</span>
<li>
<input class="uniform" type="checkbox" name="individual" id="individual" value="0" onclick="check(this)" />
<label>
<?= $_LANG[11]; ?>
</label>
</li>
<li>
<input class="uniform" type="checkbox" name="individual" id="individual" value="1" onclick="check(this)"/>
<label>
<?= $_LANG[12]; ?>
</label>
</li>
<li>
<input class="uniform" type="checkbox" name="individual" id="individual" value="2" onclick="check(this)" />
<label>
<?= $_LANG[13]; ?>
</label>
</li>
<li>
<input class="uniform" type="checkbox" name="individual" id="individual" value="3" onclick="check(this)" />
<label>
<?= $_LANG[14]; ?>
</label>
</li>
</ul>
</div>
</div>
<div class="da-form-row">
<label>
<?= $_LANG[134];?>
<span class="required">*</span></label>
<div class="da-form-item large"> <span class="formNote">
<?= $_LANG[135];?>
</span>
<select class="chzn-select required" name="ano_letivo">
<?
$type = $_GET['filter'];
$q
->select()
->from('user')
->where_equal_to(
array(
'cargo'=>$type
)
)
->run();
if($q){
$unit=$q->get_selected();
foreach($unit as $array){
print "<option value='".$array['id']."'>".$array['nome']."</option>";
}
}
?>
</select>
</div>
</div>
这是脚本。将其放入 head 标签内
<script>
function check(box)
{
if(box.checked==true)
{
var xmlhttp;
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
alert("success");
}
}
xmlhttp.open("GET","index.php?filter="+box.value,true);
// change index.php to your pagename and filter is the parameter you should get in your server side.
xmlhttp.send();
}
}
</script>
关于php - 使用复选框 ajax 更改查询，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18177807/