mysql - 获取不同位置的访问计数

Question

访问 mysql表:

+---------+-------------+------------+--------+---------------------+
| visitId | visitSiteId | homeSiteId | userId |       time          |
+---------+-------------+------------+--------+---------------------+
|   1     |      1      |     1      |  1001  | 2013-09-01 11:50:12 |
|   2     |      1      |     1      |  1001  | 2013-09-03 12:50:12 |
|   3     |      2      |     1      |  1001  | 2013-09-04 13:50:12 |
|   4     |      2      |     1      |  1001  | 2013-09-07 11:00:00 |
|   5     |      2      |     1      |  1001  | 2013-09-09 12:32:12 |
|   6     |      2      |     1      |  1001  | 2013-09-13 15:48:12 |
|   7     |      2      |     2      |  1002  | 2013-09-01 11:00:12 |
|   8     |      2      |     2      |  1002  | 2013-09-02 12:50:12 |
|   9     |      2      |     2      |  1002  | 2013-09-05 13:50:12 |
|   10    |      1      |     2      |  1002  | 2013-09-06 11:50:12 |
|   11    |      1      |     2      |  1002  | 2013-09-07 12:50:12 |
|   12    |      2      |     2      |  1002  | 2013-09-15 13:50:12 |
+---------+-------------+------------+--------+---------------------+

记录访问日期时间、访问的网站和用户主页

我想找到如何从上面的数据输出 3 个报告。

1. 返回非主网站访问次数 >= 主网站访问次数的所有用户；任意日期
2. 返回非家庭网站访问次数 >= 输入的最小整数的所有用户，例如非家庭计数 >= 10
3. 1 和 2 均包含日期范围，即时间 >= '2013-09-01 11:50:12' AND 时间 <= '2013-09-13 15:48:12'

我对 MySQL 很陌生，并且在子查询语法方面遇到困难，因此希望得到任何帮助: 下面的查询将返回家庭访问和非家庭访问的计数，但我无法理解子查询的组合结果

SELECT COUNT(v.user_id), v.user_id FROM visit v WHERE v.Site <> v.HomeSite GROUP BY v.user_id;
SELECT COUNT(v.user_id), v.user_id FROM visit v WHERE v.Site = v.HomeSite GROUP BY v.user_id;
SELECT COUNT(v.user_id), v.user_id FROM visit v WHERE v.Site <> v.HomeSite AND v.Time >= '2013-09-01 11:50:12' AND v.Time <= '2013-09-13 15:48:12' GROUP BY v.user_id;
SELECT COUNT(v.user_id), v.user_id FROM visit v WHERE v.Site = v.HomeSite AND v.Time >= '2013-09-01 11:50:12' AND v.Time <= '2013-09-13 15:48:12' GROUP BY v.user_id;

这里是MySQL创建表和插入数据以协助测试:

 CREATE TABLE `dbName`.`visit`(`visitId` INT(11) NOT NULL AUTO_INCREMENT, `visitSiteId` INT(11), `homeSiteId` INT(11), `userId` INT(11), `time` DATETIME, PRIMARY KEY (`visitId`));

INSERT INTO `dbName`.`visit`(`visitSiteId`,`homeSiteId`,`userId`,`time`) VALUES
  (1,1,1001,'2013-09-01 11:50:12'),
  (1,1,1001,'2013-09-03 12:50:12'),
  (2,1,1001,'2013-09-04 13:50:12'),
  (2,1,1001,'2013-09-07 11:00:00'),
  (2,1,1001,'2013-09-09 12:32:12'),
  (2,1,1001,'2013-09-13 15:48:12'),
  (2,1,1002,'2013-09-01 11:00:12'),
  (2,1,1002,'2013-09-02 12:50:12'),
  (2,1,1002,'2013-09-05 13:50:12'),
  (1,1,1002,'2013-09-06 11:50:12'),
  (1,1,1002,'2013-09-07 12:50:12'),
  (2,1,1002,'2013-09-15 13:50:12');

Answer 1

未经尝试和测试..

SELECT Count(visitId) AS Visits, userId 
    FROM homeSiteId 
    GROUP BY visitId HAVING Count(visitId) > 2999