嗨，我正在尝试弄清楚如何在抓取数据后将其保存到 mysql 中。 它不会将任何内容插入数据库。我认为这是因为我传递的数据格式不正确？我需要通过 json 发布这个吗？
<head>
<link rel="stylesheet" href="styles.css" type="text/css">
</head>
<?php
//echo phpinfo();
//include the php class to get the div content
include_once('simple_html_dom.php');//http:
include_once('dbconn.php');
//the name of the curl function
function curl_get_contents($url){
//Initiate the curl
$ch=curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
//removes the header of the webpage
curl_setopt($ch, CURLOPT_HEADER, 0);
//do not display the whole page
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
//execute the curl
$output = curl_exec($ch);
//close the curl so that resources are not wasted
//curl_close($ch);
return $output;
ini_set('max_execution_time', 3000); //300 seconds = 5 minutes
}
$output = curl_get_contents('http://www.lockweb.com.au/en/site/lockweb/Products/? groupId=469&productId=135');
// Get the complete html from the address
$html = str_get_html($output);
//get the title
$title = $html->find('div.content-wide[id=content]', 0);
$description = $html->find('div[class="tab-content content-wide selected"]',0);
$spec = $html->find('div[class="tab-content content-wide"]',0);
$moreinfo = $html->find('div[id=downloadsitem]',0);
$image = $html->find('div.product-presentation',0);
$echoHTML = "<table border=1 align=center>";
$echoHTML .="<tr>";
/* adding rows header to table */
$echoHTML .="<th>Title</th>";
$echoHTML .="<th>Description</th>";
$echoHTML .="<th>Specifications</th>";
$echoHTML .="<th>MoreInfo</th>";
$echoHTML .="<th>Image/s</th>";
$echoHTML .="</tr>";
$echoHTML .="<tr>";
$echoHTML .="<td>".$title->plaintext."</td>";
$echoHTML .="<td>".$description->plaintext."</td>";
$echoHTML .="<td>".$spec."</td>";
$echoHTML .="<td>".$moreinfo."</td>";
$echoHTML .="<td>".$image."</td>";
/* end of table */
$echoHTML .= "</table>";
echo $echoHTML;
//trying to insert the data into the database
$q= ("INSERT INTO `lockwood`.`products` (
`Title` ,
`Descr` ,
`Spec` ,
`more info` ,
`image` ,
`id`
)
VALUES (
'$title', 'teat', 'test', 'test', 'test', NULL"
);
?>
最佳答案
您正在废弃数据并正确生成表格...
正如您所说，当您尝试将 html 代码插入数据库时会发生问题...
此代码必须使用 mysql_real_escape_string() 进行转义
$q= sprintf(("INSERT INTO `lockwood`.`products` (
`Title` ,
`Descr` ,
`Spec` ,
`more info` ,
`image` ,
`id`
)
VALUES (
'%s', 'teat', 'test', 'test', 'test', NULL"
), mysql_real_escape_string($title));
或者
$q= ("INSERT INTO `lockwood`.`products` (
`Title` ,
`Descr` ,
`Spec` ,
`more info` ,
`image` ,
`id`
)
VALUES (
' {mysql_real_escape_string($title)} ', 'teat', 'test', 'test', 'test', NULL"
);
不幸的是，此功能已被弃用，并将在将来被删除...因此，根据您的需要，使用 mysqli_real_escape_string()或PDO::quote()
关于php - 使用 Simple Dom Parser 将 cURL 数据插入 mysql 时遇到问题，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/19129769/