php - 如何为行添加值？

Question

我正在尝试创建类(class)记录。我创建了一个表，其中包含名称和事件列。

表格看起来像这样。

Name   |    Q1    |    Q2      |
--------------------------------
Prinz  |    20    | (input text)

My aim is to save the input data into my database, but I need to have the id of the student(Prinz). I already managed to save the grade but want the id of that particular student to be save as well. My MYSQL table has 4 att. namely, grade_id(auto_inc), stud_id, grade and the activity type(Quiz, Assignment, Exam).

Here's my code

<table border="0" cellspacing="0" cellpadding="0" style="width: 845px; margin-top: 20px; margin-bottom: 65px;">
            <tr style="background-color: #caccca; text-align: center;">
            <td style="width: 130px;" class="td-1">NAME</td>
            <?php 
            $result = mysql_query("select * from subject_grade ");
            $numrows = mysql_num_rows($result);
            while ($row = mysql_fetch_object($result)) {
            $act_type = $row->act_type;
            echo '<td style="width: 130px;" class="td-1">'.$row->act_type .'</td>';
            }
            ?>
            <td class="td-1">GPA</td>
            </tr>
            <?php 

            $result = mysql_query("select * from student_db ");
            while ($row = mysql_fetch_object($result)) {
            echo '<tr class="border" style="background-color: #f9f9f9;"><td style="width: 150px;" class="td-2" name="student"><p>'.$row->firstname .' '. $row -> lastname .'</p></td>';

                $id = $row->student_id;
                for ($i=0; $i<$numrows; $i++){
                    echo '<form action ="record.php" method="POST"><td style="text-align: center;"><input type="text "style="font-size: 12px; width: 20px;" name="grade"><input style="display: none;" type="text" name="id" value="'.$id.'"><input type="submit"></td></form>';
                }
            echo '<td style="width: 80px;"class="td-2"></td>';
            }

            ?>

            </tr>
        </table>

RECORD.PHP 文件

if($_POST['grade']){
        $sql="INSERT INTO class_record (grade, student_id)
        VALUES
        ('$_POST[grade]','$_POST[id]')";

        $rs1 = mysqli_query($con,$sql);
        echo $_POST['grade'] .' '. $studID;

} else echo 'ERROR';

？>

我希望你能帮助我，这是我们学校的项目。

Answer 1

请更改您的查询，您的查询有误， 改变

$sql="INSERT INTO class_record (grade, student_id)
        VALUES
        ('$_POST[grade]','$_POST[id]')";

与

$sql="INSERT INTO class_record (grade, student_id)
        VALUES
        ('".$_POST['grade']."','".$_POST['id']."')";