我有一个 PHP 数组
$array = array(
"PHP server side scripting",
"CSE for designing",
"Client side scripting JavaScript, HTML etc",
"Java object oriented programming"
}
还有一个数据库表
+-------+-----------------+
| id | language |
+-------+-----------------+
| 1 | PHP |
| 2 | JavaScript |
| 3 | CSE |
| 4 | C++ |
+-------+-----------------+
如何使用查询将数组项与数据库表的字段部分匹配。
所需输出仅与 PHP 数组匹配的语言
+-------+-----------------+
| id | language |
+-------+-----------------+
| 1 | PHP |
| 2 | JavaScript |
| 3 | CSE |
+-------+-----------------+
我尝试过以下操作,但没有得到实际结果。
foreach($array as $val) {
$sql = "SELECT * FROM my_table WHERE language LIKE '%$val%'";
//remaining code
}
提前致谢。
最佳答案
从数据库获取所有语言然后检查数组中有哪些语言会更容易。
如果您想在查询中使用它,那么您必须执行以下操作:
$array = array(
"PHP server side scripting",
"CSE for designing",
"Client side scripting JavaScript, HTML etc",
"Java object oriented programming"
);
foreach($array as $val) {
$valArray = explode(" ", $val);
$where = "";
foreach ($valArray as $word) {
$word = trim($word, ",.");
if ($where) {
$where .= " OR ";
}
$where .= " language LIKE '%$word%' ";
}
$sql = "SELECT * FROM my_table WHERE $where";
//remaining code
}
但这是一个丑陋的解决方案
关于PHP 数组项与数据库表部分匹配,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19731474/