你能帮我完成这个项目吗?我确实研究了之前提出的问题,但它们似乎没有解决这种独特的情况。
示例数据:
Member | DOS | Dx1 | Dx2 | Dx3 | Dx4 | Dx5
12345 | 1/1/2011 | 12142 | 12345 | 65657 | 5657 | 568
56484 | 3/5/2011 | 568 | 56785 | 5695 | 575 | 168
56872 | 2/12/2011 | 567 | 567 |
我需要看到的是:
Member DOS DX Seq
12345 1/1/2011 12142 Dx1
12345 1/1/2011 12345 Dx2
12345 1/1/2011 65657 Dx3
等等。仅显示那些不为空的 Dx,因此对于 56872,我们只会看到 Dx1 和 Dx2,但对于其他 2 个,我们会看到所有 5 个 Dx 的记录。
有人可以帮助我吗? 谢谢。
最佳答案
这种类型的数据转换称为UNPIVOT
。不幸的是,MySQL 没有 unpivot 功能,但您可以通过几种不同的方式复制该功能。
您可以使用 UNION ALL
查询将每个列值转换为行:
select member, dos, dx, seq
from
(
select member, dos, dx1 as dx, 'Dx1' as seq
from yourtable
union all
select member, dos, dx2 as dx, 'Dx2' as seq
from yourtable
union all
select member, dos, dx3 as dx, 'Dx3' as seq
from yourtable
union all
select member, dos, dx4 as dx, 'Dx4' as seq
from yourtable
union all
select member, dos, dx5 as dx, 'Dx5' as seq
from yourtable
) d
where dx is not null
order by member, seq;
参见SQL Fiddle with Demo 。此方法将为您提供结果,但在较大的表上可能不是很有效。
另一种方法是在虚拟表上使用 CROSS JOIN:
select member, dos, dx, seq
from
(
select t.member, t.dos,
case s.seq
when 'Dx1' then dx1
when 'Dx2' then dx2
when 'Dx3' then dx3
when 'Dx4' then dx4
when 'Dx5' then dx5
end DX,
s.seq
from yourtable t
cross join
(
select 'Dx1' as seq union all
select 'Dx2' as seq union all
select 'Dx3' as seq union all
select 'Dx4' as seq union all
select 'Dx5' as seq
) s
) d
where dx is not null
order by member, seq;
参见SQL Fiddle with Demo 。两者都给出结果:
| MEMBER | DOS | DX | SEQ |
|--------|---------------------------------|-------|-----|
| 12345 | January, 01 2011 00:00:00+0000 | 12142 | Dx1 |
| 12345 | January, 01 2011 00:00:00+0000 | 12345 | Dx2 |
| 12345 | January, 01 2011 00:00:00+0000 | 65657 | Dx3 |
| 12345 | January, 01 2011 00:00:00+0000 | 5657 | Dx4 |
| 12345 | January, 01 2011 00:00:00+0000 | 568 | Dx5 |
关于mysql - 高效地将列转为行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20734820/