如何在表中提交多个值请帮助我使用此代码 此代码仅在数据库中提交 1 个条目，但我想在数据库中输入多个值，我该怎么做
现场演示 http://jsfiddle.net/eruZC/3/
这是entry.html
<script type='text/javascript' src='http://code.jquery.com/jquery-1.10.1.js'></script>
<link rel="stylesheet" type="text/css" href="http://fiddle.jshell.net/css/result-light.css">
<style type='text/css'>
</style>
<script type='text/javascript'>//<![CDATA[
$(window).load(function(){
$(document).ready(function(){
var id=1;
$("#butsend").click(function(){
$("#table1").append('<tr valign="top"><td width="100px">'+(id++)+'</td><td width="100px">'+$("#sname").val()+'</td><td width="100px">'+$("#age").val()+'</td><td width="100px"><a href="javascript:void(0);" class="remCF">Remove</a></td></tr>');
});
$("#table1").on('click','.remCF',function(){
$(this).parent().parent().remove();
});
});
});//]]>
</script>
</head>
<body>
<form action="submit.php" d="form1" name="form1" method="post">
<label>Student Name</label><input type="text" name="sname" id="sname"></br>
<label>Student Age</label><input type="text" name="age" id="age"></br>
<input type="button" name="send" value="Add" id="butsend"></br>
<input type="button" name="submit" value="Submit" ></br>
</form>
<table id="table1" name="table1" border="">
<tbody>
<tr><th width="100px">ID</th><th width="100px">Name</th><th width="100px">Age</th><th width="100px"></th><tr>
</tbody>
</table>
</body>
</html>
这是php页面submit.php
<?php
/*
NEW.PHP
Allows user to create a new entry in the database
*/
// creates the new record form
// since this form is used multiple times in this file, I have made it a function that is easily reusable
function renderForm($sname, $age, $error)
{
?>
<?php
// if there are any errors, display them
if ($error != '')
{
echo '<div style="padding:4px; border:1px solid red; color:red;">'.$error.'</div>';
}
?>
<?php
}
// connect to the database
include('connect-db.php');
// check if the form has been submitted. If it has, start to process the form and save it to the database
if (isset($_POST['submit']))
{
// get form data, making sure it is valid
$sname = mysql_real_escape_string(htmlspecialchars($_POST['sname']));
$age = mysql_real_escape_string(htmlspecialchars($_POST['age']));
// check to make sure both fields are entered
if ($name == '')
{
// generate error message
$error = 'ERROR: Please fill in all required fields!';
// if either field is blank, display the form again
renderForm($sname, $age, $error);
}
else
{
// save the data to the database
mysql_query("INSERT stock SET sname='$sname', age='$age'")
or die(mysql_error());
// once saved, redirect back to the view page
}
}
else
// if the form hasn't been submitted, display the form
{
renderForm('','','','','','','','');
}
?>
最佳答案
如果您想从单个表单添加多个值，请在输入框中添加逗号分隔值，然后使用explodeegp>
$sname = mysql_real_escape_string(htmlspecialchars($_POST['sname']));
$namearray = explode(',',$sname);
foreach ($namearray as $sname){
mysql_query("INSERT stock SET sname='$sname', age='$age'")
or die(mysql_error());
}
关于javascript - 如何使用php和jquery在mysql中提交多个数据，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/20837694/