SELECT *
FROM app_detailsvvv as dtable
WHERE primaryGenreName='".$ov['title']."'
AND composed='1' AND
(SELECT COUNT(*) as c
FROM new_apps
WHERE trackId=dtable.trackId AND top>0) > 0
ORDER BY top ASC
我在这里想要做的是ORDER BY
表new_apps的顶部而不是app_detailsvvv
,因为它甚至没有顶部字段,该怎么做?
最佳答案
为此使用INNER JOIN
。这将是您的查询:
SELECT dtable.* FROM app_detailsvvv as dtable
INNER JOIN new_apps ON new_apps.trackId=dtable.trackId
WHERE primaryGenreName='".$ov['title']."'
AND composed='1' AND
(SELECT COUNT(*) as c
FROM new_apps
WHERE trackId=dtable.trackId AND top>0) > 0
ORDER BY new_apps.top ASC
关于mysql - 有一个 mysql 查询,我希望能够从第二个表运行 order by,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21568679/