mysql - yii 查询 CActiveDataProvider 上的 4 个表

Question

嗨，主人，我有 4 张 table

-pekawai -佩尼拉安 -大学 -jurusan

我通常使用

    SELECT  u.nama_univ, j.singkatan, peg.* FROM pegawai AS peg LEFT JOIN penilaian AS pen ON pen.no_test=peg.no_test LEFT JOIN universitas AS u ON u.id=peg.univ_s1 LEFT JOIN jurusan AS j ON j.id=peg.bidang_s1

如何将此查询转换为 yii ？

我已经尝试过这段代码，但效果不佳

$dataProvider = new CActiveDataProvider('Pegawai', array(
    'criteria' => array(
        'select' => array(
            '`pen`.*',
            '`u`.`nama_univ` AS `nama_univ`',
            '`j`.`singkatan` AS `singkatan`'
        ),
        'join' => 'JOIN `Penilaian` AS `pen` ON `pen`.`no_test` = `t`.`no_test`',
        'join' => 'JOIN `Universitas` AS `u` ON `u`.`id` = `t`.`no_test`',
        'join' => 'JOIN `Jurusan` AS `j` ON `j`.`id` = `t`.`no_test`',
    )
));

但只有一个连接执行

Answer 1

做一件事，只需打印标准对象，例如

$dataProvider = new CActiveDataProvider('Pegawai', array(
    'criteria' => array(
        'select' => array(
            '`pen`.*',
            '`u`.`nama_univ` AS `nama_univ`',
            '`j`.`singkatan` AS `singkatan`'
        ),
        'join' => 'JOIN `Penilaian` AS `pen` ON `pen`.`no_test` = `t`.`no_test`',
        'join' => 'JOIN `Universitas` AS `u` ON `u`.`id` = `t`.`no_test`',
        'join' => 'JOIN `Jurusan` AS `j` ON `j`.`id` = `t`.`no_test`',
    )
));
echo "<pre>";
print_r($dataProvider);   //Check the object or try to post it below
exit();