mysql - 基于 MySQL 具有相同行值的特定列对列进行排名

Question

我想创建一些东西，通过查询对距离用户最近的距离进行排名。现在唯一的问题是我不知道如何为 MySQL 实现它。我正在考虑像 Oracle 中实现的排名分区之类的东西。现在这是我的查询:

SELECT  p.idproduct,
p.common_name,
ROUND(
SQRT(
    POW(69.1 * (s.store_lat - 4.946966), 2) +
    POW(69.1 * (114.960770 - s.store_long) * COS(s.store_lat / 57.3), 2)),2) AS distance
FROM    product p
        INNER JOIN branches b
            ON b.idproduct = p.idproduct
        INNER JOIN store s
            ON b.idstore = s.idstore
        INNER JOIN
        (   SELECT DISTINCT p.common_name
            FROM    shopping_list_content s
                    INNER JOIN product p
                        ON s.iditem = p.idproduct
            WHERE   s.idlist =64
        ) s
            ON s.common_name = p.common_name

现在它的结果如下:

idproduct | common_name | distance
1         | item 1      |   0
1         | item 1      |   1
2         | item 2      |   3
2         | item 2      |   1
3         | item 3      |   2
3         | item 3      |   0

并添加了我应该获得的排名:

idproduct | common_name | distance | rank
1         | item 1      |   0      | 1
1         | item 1      |   1      | 2
2         | item 2      |   3      | 2
2         | item 2      |   1      | 1
3         | item 3      |   2      | 2
3         | item 3      |   0      | 1

最后通过嵌套选择我将得到:

idproduct | common_name | distance | rank
1         | item 1      |   0      | 1
2         | item 2      |   1      | 1
3         | item 3      |   0      | 1

我在这里看到了类似 @curRank 的内容 ( Rank function in MySQL )，但不确定如何根据当前的查询来实现它。

我尝试对 common_name 列使用 GROUP BY，但我想这完全不是正确的方法。希望有人能帮忙。

Answer 1

此查询在 MySQL 中运行良好以进行排名:

SELECT TAB1.idproduct,TAB1.common_name,TAB1.distance,
(TAB1.RN - TAB2.MN) + 1 RANK FROM
(SELECT T1.*,@ROWNUM := @ROWNUM + 1 RN FROM
(SELECT * FROM (SELECT  p.idproduct,
p.common_name,
ROUND(
SQRT(
POW(69.1 * (s.store_lat - 4.946966), 2) +
POW(69.1 * (114.960770 - s.store_long) * COS(s.store_lat / 57.3), 2)),2) AS distance
FROM    product p
    INNER JOIN branches b
        ON b.idproduct = p.idproduct
    INNER JOIN store s
        ON b.idstore = s.idstore
    INNER JOIN
    (   SELECT DISTINCT p.common_name
        FROM    shopping_list_content s
                INNER JOIN product p
                    ON s.iditem = p.idproduct
        WHERE   s.idlist =64
    ) s
        ON s.common_name = p.common_name)TABLE1 
ORDER BY idproduct,common_name,distance)T1,
(SELECT @ROWNUM := 0) RN)TAB1
INNER JOIN
(SELECT T2.*,MIN(RN) MN FROM
(SELECT T1.*,@ROWNUM := @ROWNUM + 1 RN FROM
(SELECT * FROM (SELECT  p.idproduct,
p.common_name,
ROUND(
SQRT(
POW(69.1 * (s.store_lat - 4.946966), 2) +
POW(69.1 * (114.960770 - s.store_long) * COS(s.store_lat / 57.3), 2)),2) AS distance
FROM    product p
    INNER JOIN branches b
        ON b.idproduct = p.idproduct
    INNER JOIN store s
        ON b.idstore = s.idstore
    INNER JOIN
    (   SELECT DISTINCT p.common_name
        FROM    shopping_list_content s
                INNER JOIN product p
                    ON s.iditem = p.idproduct
        WHERE   s.idlist =64
    ) s
        ON s.common_name = p.common_name)TABLE1 
ORDER BY idproduct,common_name,distance)T1,
(SELECT @ROWNUM := 0) RN)T2
GROUP BY idproduct,common_name)TAB2
ON TAB1.idproduct = TAB2.idproduct AND
TAB1.common_name = TAB2.common_name;

SQL Fiddle