mysql - SQL 显示 count() 中的值

Question

所以我有两个表:

  People                    Jobs

id | name            id | personId | Status | place
--------------      ---------------------------------
1  | John            1  |    1     | Active | Home
2  | Melinda         2  |    1     | Active | Office
3  | Samuel          3  |    2     | Active | Home
                     4  |    3     | Active | Office
                     5  |    1     | Active | Garden

问题:

我想显示在家庭或办公室拥有不止一项事件工作的人员的姓名。我可以计数并显示数字，但无法显示名称。

这是我的代码(不起作用):

SELECT t.name 
FROM people p JOIN jobs j ON j.personId = p.id
WHERE j.status = 'Active' AND j.place='Home' OR j.place='Office' 
HAVING count(j.personId) > 1 

Answer 1

AND 和 OR 在 WHERE 条件下混合:

改变这个

 WHERE j.status = 'Active' AND j.place='Home' OR j.place='Office'

至

  WHERE j.status = 'Active' AND (j.place='Home' OR j.place='Office')

试试这个

 SELECT p.name 
 FROM People p JOIN jobs t ON t.personId = p.id
 WHERE t.status = 'Active' AND (t.place='Home' OR t.place='Office')
 GROUP BY p.name
 HAVING count(t.personId) > 1 

DEMO HERE