我有这段代码来获取两个日期$date1
和$date2
之间的记录
for ($i=$date1;$i<$date2;$i++){//BETWEEN THE TWO DATES
$count_rcvd=mysql_num_rows(mysql_query("select * from cards where Date_Rcvd='$i'"));
$count_collect=mysql_num_rows(mysql_query("select * from cards where Date_Collected='$i'"));
if($i==$date1){FOR THE FIRST DATE IN THE RANGE
$uncollected=mysql_num_rows(mysql_query("select * from cards where Status='AVAILABLE' and Date_Rcvd<='$i'"));
$balance=$uncollected;
}
else{//FOR CONSECUTIVE DATES AFTER DATE1
$uncollected=mysql_num_rows(mysql_query("select * from cards where Status='AVAILABLE' and Date_Rcvd<'$i'"));//previous days balance
$balance=$uncollected+$count_rcvd-$count_collect;
当我回显 $i 时
echo “”;
回显$i;
echo “”;
回显 $count_rcvd;
echo “”;
回显 $count_collect;
echo “”;
回显$余额;
回显“”;
我在下面得出的日期远远超出了日历日期
014-03-15 0 7 103
2014-03-16 0 3 100
2014-03-17 0 7 96
2014-03-18 0 9 94
2014-03-19 0 5 98
2014-03-20 15 6 112
2014-03-21 0 6 103
2014-03-22 0 1 108
2014-03-23 0 0 109
2014-03-24 0 8 101
2014-03-25 0 3 106
2014-03-26 0 0 109
2014-03-27 1 2 108
2014-03-28 0 0 110
2014-03-29 6 1 115
2014-03-30 0 0 116
2014-03-31 0 0 116
2014-03-32 0 0 116
2014-03-33 0 0 116
2014-03-34 0 0
问题是输出日期超出了例如 31 日......帮助!!!
最佳答案
要迭代日期,我建议您使用 DateTime 和 DateTimeInterval 类(小心!最低 PHP 5.3):http://www.php.net/manual/fr/class.datetime.php
您可以按照真实日历添加天/月:http://www.php.net/manual/fr/datetime.add.php
关于php - php mysql 两个日期之间的记录数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22907737/