我有 REPLACE 的 SQL 语法
$query = "REPLACE INTO ".TBL_ACTIVE_ADMINS." VALUES (:username, :time, :userlevel)";
$stmt = $this->connection->prepare($query);
$stmt->execute(array(':username' => $username, ':time' => $time, ':userlevel' => $userlevel));
这工作正常,但我想稍微调整一下,以便其中有一个 where 子句只允许 :userlevel 为“9”我使用 REPLACE SELECT 尝试了此操作,但我不断收到错误
$query = "REPLACE INTO ".TBL_ACTIVE_ADMINS."(:username, :time, :userlevel) SELECT * FROM ".TBL_USERS." WHERE userlevel = 9 SET username = :username and timestamp = :time and userlevel = :userlevel";
$stmt = $this->connection->prepare($query);
$stmt->execute(array(':username' => $username, ':time' => $time, ':userlevel' => $userlevel));
谁能向我解释一下我在上面的代码中做错了什么?
最佳答案
没关系;在对代码进行了很多修改之后,我决定从不同的角度来看待它。我现在已经编写了一个函数,可以在每次刷新页面时清理 SQL 表,从而准确地统计出当前在我的网站上活跃的用户。
我使用了下面的代码,然后在调用计数之前我清理了数据库表
$query = "REPLACE INTO ".TBL_ACTIVE_ADMINS." VALUES (:username, :time, :userlevel)";
$stmt = $this->connection->prepare($query);
$stmt->execute(array(':username' => $username, ':time' => $time, ':userlevel' => $userlevel));
所以我的最终代码看起来像这样
$query = "REPLACE INTO ".TBL_ACTIVE_ADMINS." VALUES (:username, :time, :userlevel)";
$stmt = $this->connection->prepare($query);
$stmt->execute(array(':username' => $username, ':time' => $time, ':userlevel' => $userlevel));
$query = "DELETE FROM ".TBL_ACTIVE_ADMINS." WHERE userlevel = 3";
$stmt = $this->connection->prepare($query);
$stmt->execute(array(':userlevel' => $userlevel));
$this->calcNumActiveAdmins();
关于mysql - REPLACE INTO SQL 语法错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22966296/