php - Mysql查询，选择join两个表

Question

我有一个 LIKE 表和一个 BOOK 表以及我的 user_id。

我只想从图书表中提取我喜欢的图书名称和作者

我的 json 将会:

{book_id:1,bookname:sample,author:sean,user_id:111}

表格

-----------BOOK TABLE------------
ID ---- BOOK AUTHOR ---- BOOK NAME

1
2

...................................


USERS TABLE
ID-------NAME
1
2
.............

LIKE TABLE---------------------------
ID-----BOOK ID-------LIKER USER ID---
1
2
.....................................

Answer 1

$stmt = $mysqli->prepare("SELECT book.*, users.*, like.* FROM like INNER JOIN
                          users ON like.liker_user_id = users.id INNER JOIN
                          book ON like.book_id = book.id WHERE
                          users.id = ?
                         ");
$stmt->bind_param( "d", $user_id); 

$stmt->execute();

$stmt->bind_result($col1);
// then fetch and close the statement