php - 如果数组元素位于 2 个日期之间，则回显文本 PHP

Question

我有以下 PHP 代码，我的目标是创建一封 HTML 电子邮件，该电子邮件应输出到期日期在 2 个设定日期之间的所有模型的详细信息:

$sql = 'SELECT
GROUP_CONCAT(op.products_model),
GROUP_CONCAT(products.products_warranty_default),
GROUP_CONCAT(orders.date_purchased),
orders.customers_name
FROM orders_products op
INNER JOIN products
    ON op.products_id = products.products_id
INNER JOIN orders
    ON op.orders_id = orders.orders_id
INNER JOIN customers
    ON orders.customers_id = customers.customers_id
GROUP BY op.orders_id';

$result = mysql_query($sql, $connection);

while ($data = mysql_fetch_row($result)) {
    $models = explode(",",$data[0]); // create array from all models in the GROUP_CONCAT
    $years = explode(",",$data[1]); // create array from all years in the GROUP_CONCAT
    $dates = explode(",",$data[2]); // create array from all dates in the GROUP_CONCAT
    $name = $data[3];
    echo $header; // header of email (only the name changes on each loop)
    foreach ($models as $index => $model) {
    echo '
    <tr>
        <td width="149">
            <center>'.$model.'</center>
        </td>
        <td width="149">
            <center>'.date('d/m/Y', strtotime('+'.$years[$index].' years', strtotime($dates[$index]))).'</center>
        </td>
    </tr>'; // echos the model in first column and date+years in second column
    }
    echo $footer; // static HTML again like the header
}

我所困扰的是，如果表中存在日期介于 2 个日期(即 2014 年 5 月 1 日和 2014 年 5 月 31 日)之间的模型，如何仅输出页眉、表格和页脚的组合。目前正在输出所有日期。

我尝试了各种方法来做到这一点，但在大约 6 个小时的失败之后，我准备把我的电脑扔出窗外。我只有几周的 PHP 经验(以及与此相关的编程经验)，因此它可能(希望)是一个我不知道的简单修复。

注意:我应该注意，使用我用来测试的当前数据库，我可以修改选择查询以输出相关日期，但在我正在使用的实际数据库上(我只能在工作中访问)没有保修字段，我必须通过 php 从产品的详细描述中提取信息并将其输入到函数中。

最终代码:

$sql = 'SELECT  op.products_model, 
        products.products_warranty_default,
        orders.date_purchased,
        orders.customers_name
   FROM orders_products op
  INNER JOIN products  ON op.products_id = products.products_id
  INNER JOIN orders    ON op.orders_id = orders.orders_id
  INNER JOIN customers ON orders.customers_id = customers.customers_id
  ORDER BY orders.customers_name, op.orders_id,
           op.products_model,
           products.products_warranty_default,
           orders.date_purchased';
$result = mysql_query($sql, $connection);
$previous_name = "";

while ($data = mysql_fetch_row($result)) {
    $model = $data[0];
    $year = $data[1];
    $date = $data[2];
    $name = $data[3];
    $expiry = strtotime('+'.$year.' years', strtotime($date));
    if ($previous_name != $name && $expiry >= strtotime('2014-05-01') && $expiry <= strtotime('2014-05-31')) {  // on a new customer name ...
        if ($previous_name != "") {
            // if there is a previous customer, write the footer
            echo $footer;
            $previous_name = $name; 
        }
    }
    if ($expiry >= strtotime('2014-05-01') && $expiry <= strtotime('2014-05-31')){
    echo '
    <tr>
        <td width="149">
                <center>'.$model.'</center>
        </td>
        <td width="149">
            <center>'.date('d/m/Y', $expiry).'</center>
        </td>
    </tr>'; // echos the model in first column and date+years in second column
    }
}
if ( $previous_name != "" && $expiry >= strtotime('2014-05-01') && $expiry <= strtotime('2014-05-31')) {
    echo $footer;
}

Answer 1

您在 SQL 查询中聚合了很多内容，然后在 PHP 中将其分解，这似乎有点奇怪。我相信这会让你很难匹配日期。

您可以尝试这个非聚合查询:

SELECT  op.products_model, 
        products.products_warranty_default,
        orders.date_purchased,
        orders.customers_name
   FROM orders_products op
  INNER JOIN products  ON op.products_id = products.products_id
  INNER JOIN orders    ON op.orders_id = orders.orders_id
  INNER JOIN customers ON orders.customers_id = customers.customers_id
  WHERE orders.date_purchased >= DATE('2014-05-01')
    AND orders.date_purchased <  DATE('2014-05-31') + INTERVAL 1 DAY
  ORDER BY orders.customer_name, op.orders_id,
           op.products_model,
           products.products_warranty_default,
           orders.date_purchased,

这将为您返回详细记录，即与日期范围匹配的记录。

我认为，使用 php 处理该结果集非常容易。您需要检测客户名称的更改才能输出页眉和页脚。这就是 $previous_name 的意义。

$previous_name = "";

while ($data = mysql_fetch_row($result)) {
    $model = $data[0];
    $year = $data[1];
    $date = $data[2];
    $name = $data[3];

    if ($previous_name != $name) {  /* on a new customer name ... */
        if ($previous_name != "") {
            /* if there is a previous customer, write the footer  */
            echo $footer; /* static HTML again like the header */
        }
        /* write the header for the new customer */
        echo $header; 
        /* pick up the new customer name */
        $previous_name = $name; 
    }
    echo '
    <tr>
        <td width="149">
            <center>'.$model.'</center>
        </td>
        <td width="149">
            <center>'.date('d/m/Y', strtotime('+'.$year.' years', 
                      strtotime($date))).'</center>
        </td>
    </tr>'; /* echos the model in first column and date+years in second column */
    }
} /* end while ($data... */

/* wrap up the report by writing the final footer if need be */
if ( $previous_name != "" ) {
    echo $footer; /* static HTML again like the header */
}    

看看进展如何？您从 SQL 请求详细结果集，然后使用 PHP 中的一些编程技术将该结果集逐个客户划分。

这比获取分组结果集然后尝试取消分组更容易、更可靠。