我正在尝试使用 Doctrine2 QueryBuilder 创建查询。
$qb = $this->getObjectManager()->createQueryBuilder();
$qb->select( array('n', 't', 'c') )
->from('Application\Entity\Notification', 'n')
->leftJoin('n.notificationType', 't')
->leftJoin('n.course', 'c')
->leftJoin('c.studyCourses', 's');
实体类(class)中的相关代码如下所示:
/**
* @ORM\OneToMany(targetEntity="StudyCourses", mappedBy="Course", cascade={"all"})
*/
protected $studyCourses;
实体StudyCourse中的相关代码如下所示:
/**
* @ORM\ManyToOne(targetEntity="Course", inversedBy="studyCourses")
* @ORM\JoinColumn(name="Course", referencedColumnName="Id", nullable=true)
*/
protected $course;
现在,当我尝试运行查询时,我在“”附近遇到语义错误。我认为打印 Doctrine 创建的 SQL 可以为我提供有关此错误的更好信息,但事实上它是:
SELECT n0_.Id AS Id0, n0_.Timestamp AS Timestamp1, n0_.TitleHtml AS TitleHtml2, n0_.ContentHtml AS ContentHtml3, n1_.Id AS Id4, n1_.Created AS Created5, n1_.Updated AS Updated6, n1_.Name AS Name7, c2_.Id AS Id8, c2_.Created AS Created9, c2_.Updated AS Updated10, c2_.Name AS Name11, c2_.Description AS Description12, c2_.Code AS Code13, c2_.ObjectId AS ObjectId14, c2_.IsActive AS IsActive15, n0_.NotificationType AS NotificationType16, n0_.User AS User17, n0_.Department AS Department18, n0_.Study AS Study19, n0_.Course AS Course20, n0_.Category AS Category21, c2_.Language AS Language22 FROM Notification n0_ LEFT JOIN NotificationType n1_ ON n0_.NotificationType = n1_.Id LEFT JOIN Course c2_ ON n0_.Course = c2_.Id LEFT JOIN
它在 LEFT JOIN 之后停止!
任何帮助将不胜感激,因为我真的不知道我做错了什么,也不知道如何解决这个问题。我在互联网上搜索了类似的错误,但到目前为止还没有运气。
最佳答案
尝试至少选择在 select 数组内的 StudyCourses 表中形成 leftJoin 所需的列。首先尝试获取诸如“select( array('n', 't', 'c', 's') )”之类的所有内容。有时,如果您未选择该列,它就会中断。如果这有效,不要获取 StudyCourses 表中的所有列,只需获取 select 中的相关列以形成 leftJoin,例如“s.id”。
希望这有帮助。
干杯!
关于php - Doctrine2 QB OneToMany 连接上的语义错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23929593/